How can I solve this problem in LCD method?

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How can I solve this problem in LCD method?

Mathematics
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I know the first step is to flip the second fraction but I am lost after that
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It looks like they want a different method. one denominator is 9 the other is 3x, so the LCD will be 9x.
multiply by 9x/9x
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How do you figure that the lcd is 9x
then cancel|dw:1441761977491:dw|
can you also show me the alternative method that they may want me to use?
lcd is 9x because you need one part of each thing in the denominators. so you need 3x and 9. Since 3 is a factor of both, it's 9x
This is the alternative method where you multiply by 9x/9x on top and bottom.
the other one is where you flip. did you want to go through this both ways?
im sorry i stepped out for a second I want to use the alternative way, please show me
the lcd is 9x, so you have to multiply both fractions by it and then the denominators will cancel |dw:1441762561073:dw|
understand?
I think I do now but a little kinks i need to figure out myself :)
ill work on the question with your steps for a bit, ill try to get back to this after im done
wait but, if i flip the other fraction when multiplying, doesnt the lcd change?
ok. the only thing left is to factor the new denominator (3x - 18) to 3(x - 6) then you can cancel more|dw:1441762727663:dw|
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if you're multiplying you don't use the lcd, you factor and cancel
oh, do i factor 3x-18
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yes, same solution with both methods
ah i see now

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