The equation below shows the relationship between the temperature in degrees Celsius, C, and degrees Fahrenheit, F. F = 9/5 C + 32 Which of the following formulas correctly solves for C? C = 5F - 32/9 C = 5F/9 - 32 C = 9/5 (F - 32) C = 5/9 (F - 32)

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The equation below shows the relationship between the temperature in degrees Celsius, C, and degrees Fahrenheit, F. F = 9/5 C + 32 Which of the following formulas correctly solves for C? C = 5F - 32/9 C = 5F/9 - 32 C = 9/5 (F - 32) C = 5/9 (F - 32)

Mathematics
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Can you show step-by-step because I want to know for later
When we solve for a variable we need to isolate that variable first. Isolate C Step one: do the opposite of addition which is subtraction. so we subtract -32 from both sides. |dw:1441763132933:dw|
i dont get anything lol

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Other answers:

We divide both sides by 9/5 and we see that now 9/5 cancels out on one side
okay
Tell me what You don't get, read everything I did
How do we subtract 32 from 9/5 ?
That doesn't make sense...
I didn't do that
i subtracted 32 from both sides, let me show you again
No no its fine ... what's the answer? It would be easier for me to understand
Its easier in a way because I would look back and forth on it so I would figure it out how you did it because right now im confused like heck
1 \[F = \frac{ 9 }{ 5 }C + 32 \] 2\[F-32 = \frac{ 9 }{ 5 }C\] 3 \[\frac{ 5 }{ 9 }(F-32) = C \]
Okay?
I should have just written it this way lol
so above I wrote out all the steps.
Probably its alot easier but why are the answers copied lol
Ooooh
Im look back to back I can't understand 9/5C is just switching back and forth..
Step one I subtracted 32 from both sides, and i got F - 32 = 9/5c then I divided both sides by (9/5) when you divide a fraction you flip it the denominator becomes the numerator; so it becomes (5/9) and got (5/9)(F-32) = C
I think I understand
But how do you take away the 9/5 from C
@CIAsmart you have 9/5*C right? to take it away you do the opposite of multiplication which is division. so i divided both sides by (9/5) so on one side \[\frac{ 9/5 }{ 9/5 } C = C\] (9/5)/(9/5) = 1 then I did the same thing on the other side (F-32) \[\frac{ f-32 }{ \frac{ 9 }{ 5 } } = (5/9)*(f-32)\]
Let me know if this is clear
Yes
That last part helped alot thanks sorry to waste your time nut seriously you can explain some way that I like lol so easy to understand
Don't worry, at least you understand it better now
when you divided f-32 / 9/5
you just flip it and thats it?
Think about if you're dividing the whole thing by (9/5) because if i re write it
I dont want to beg you but can you give me a question like about this with different number so I can do it myself and you can see if I did right?
\[f-32 * \frac{ 1 }{ \frac{ 9 }{ 5 } }\]
Put (1)/(9/5) in your calculator
Life must be great for you since you understand math so easily ,....
1.8
it takes some time, though. there are people on this site who are much better than I am. \[\frac{ 1 }{ \frac{ 9 }{ 5 } } = \frac{ 5 }{ 9 }\] it's called the reciprocal it means we just put 1 over that number.
Yeah yeah sorry its 5/9
I did it wrong the first time then i got my real calculator and it showed 5 over 9
you have to put the answers in brackets sometimes because the calculator gives you the wrong answer
especially when you divide numbers
Can you give me a problem just like this one so I can solve it and see what my mistakes are or if I really understand it?
ok \[\frac{ 4 }{ 5 }x + 1 = F \] I want you to solve for x
so you need to make sure that you get x by itself
this is somewhat similar to the other question you had before
we subtract 1 from each side?
5 over 4 F - 1= x
You are correct we must subtract one first BUT do it one step at a time
so first subtract one from both sides and then show me what you have now
F - 1
okay so you have F-1 = 4/5x what must you do now? to isolate x?
(F-1)\[\frac{ f-1 }{ \frac{ 4 }{ 5 }X }\]
nice but you're just dividing by 4/5 not 4/5x because we want to isolate x remember? but otherwise great
Yeah I dont know this part lol...
|dw:1441765316715:dw|
i'm a college student
So I got it right the first time?
one word: practice
yes you had it right
Wait so whats the answer?
|dw:1441765557365:dw|
YYYYEEEESSSS I GOT IT RIGHT OMGGGGG
|dw:1441765621421:dw|
LOL
absolutely take care

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