anonymous
  • anonymous
A solution with a pH of 9 has a [OH-] concentration of A. 1.0 × 10–14 mol/L. B. 1.0 × 10–9 mol/L. C. 1.0 × 10–5 mol/L. D. 1.0 × 10–7 mol/L. hELP
Chemistry
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

Jhannybean
  • Jhannybean
\[\sf pH+pOH=14\]\[\sf pOH = 14 - pH = 14 - 9 = 5\]\[\sf pOH = 5\]\[\sf 10^{-pOH} =10^{-5}\]\[\sf [OH^-] = 10^{-pOH} =10^{-5} = 1.0 ~\times 10^{-5}\]
anonymous
  • anonymous
We could go back a little further before @Jhannybean 's post and say that we found the equilibrium constant of water to be \[K_w = 10^{-14}\] which is a super tiny number, that shows that not much water dissociates into \(H^+\) and \(OH^-\). Then we can write out the equilibrium equation: \[K_w= [H^+][OH^-]\] \[10^{-14}= [H^+][OH^-]\] Now take the negative log base 10 of both sides: \[-\log_{10} 10^{-14} = -\log_{10} ([H^+][OH^-])\] Then use some log properties to take the -14 exponent down and separate the two terms on the right: \[14\log_{10} 10 = -\log_{10} [H^+] -\log_{10} [OH^-]\] Then this simplifies to the start of her answer, in case you wanted to go further back, just for fun. \[14 = pH + pOH\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.