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anonymous

  • one year ago

(2y^3+3y^2-4y-5) / (y+1) I'm missing a digit or symbol somewhere I know it.. I got the answer: 2y^2+4y Help please?

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  1. UnkleRhaukus
    • one year ago
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    did you use long division, or something else?

  2. anonymous
    • one year ago
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    Long Division

  3. UnkleRhaukus
    • one year ago
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    |dw:1441764763480:dw|

  4. UnkleRhaukus
    • one year ago
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    |dw:1441764807889:dw|

  5. UnkleRhaukus
    • one year ago
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    |dw:1441764873004:dw|

  6. UnkleRhaukus
    • one year ago
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    can you show the next step

  7. anonymous
    • one year ago
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    sure just a second

  8. anonymous
    • one year ago
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    Actually no. I['m not sure what to do with a single y.

  9. UnkleRhaukus
    • one year ago
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    whops i've made a mistake

  10. UnkleRhaukus
    • one year ago
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    * |dw:1441765132409:dw|

  11. UnkleRhaukus
    • one year ago
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    now can you do the next step? (sorry about that)

  12. anonymous
    • one year ago
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    that's ok. the next line is y^2 and y (below y^2 and 4y) which subtracts to 3y? then drop the - 5 next to it.

  13. UnkleRhaukus
    • one year ago
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    careful, the subtraction is the upper line - the lower line |dw:1441765283898:dw|

  14. UnkleRhaukus
    • one year ago
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    right?

  15. anonymous
    • one year ago
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    ok, but how is it -5y?

  16. UnkleRhaukus
    • one year ago
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    -4y - (+y) = -4y -y = -5y

  17. UnkleRhaukus
    • one year ago
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    (y^2-4y-5) - (y^2+y) = -5y -5

  18. anonymous
    • one year ago
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    Ok, lol I keep looking at the - like a minus not a negative. What's the next step?

  19. UnkleRhaukus
    • one year ago
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    only one more round to go, but there is no more room

  20. anonymous
    • one year ago
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    What do you mean?

  21. UnkleRhaukus
    • one year ago
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    |dw:1441765706793:dw|