(2y^3+3y^2-4y-5) / (y+1) I'm missing a digit or symbol somewhere I know it.. I got the answer: 2y^2+4y Help please?

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(2y^3+3y^2-4y-5) / (y+1) I'm missing a digit or symbol somewhere I know it.. I got the answer: 2y^2+4y Help please?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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did you use long division, or something else?
Long Division
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can you show the next step
sure just a second
Actually no. I['m not sure what to do with a single y.
whops i've made a mistake
* |dw:1441765132409:dw|
now can you do the next step? (sorry about that)
that's ok. the next line is y^2 and y (below y^2 and 4y) which subtracts to 3y? then drop the - 5 next to it.
careful, the subtraction is the upper line - the lower line |dw:1441765283898:dw|
right?
ok, but how is it -5y?
-4y - (+y) = -4y -y = -5y
(y^2-4y-5) - (y^2+y) = -5y -5
Ok, lol I keep looking at the - like a minus not a negative. What's the next step?
only one more round to go, but there is no more room
What do you mean?
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