InspectorJoe
  • InspectorJoe
Need help please 27x^6-8 factoring the sum or difference of cubes
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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InspectorJoe
  • InspectorJoe
\[27x ^{6}-8\]
InspectorJoe
  • InspectorJoe
keep in mind I'm factoring the sum or deference of cubues
madhu.mukherjee.946
  • madhu.mukherjee.946
what is your question

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InspectorJoe
  • InspectorJoe
27x^6-8 factoring the sum or difference of cubes
madhu.mukherjee.946
  • madhu.mukherjee.946
(3x^2)^3-2^3
InspectorJoe
  • InspectorJoe
how did we get there?
zzr0ck3r
  • zzr0ck3r
\[27x^6-8=3^3(x^2)^3-2^3=(3x^2)^3-2^3\] Now we use the difference of cubes formula that states \(a^3-b^3=(a-b)(a^2+ab+b^2)\)
zzr0ck3r
  • zzr0ck3r
Can you please delete the huge space post?
InspectorJoe
  • InspectorJoe
howhow?
InspectorJoe
  • InspectorJoe
got it thanks
InspectorJoe
  • InspectorJoe
and thanks for the help

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