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anonymous
 one year ago
Chris drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took
6
hours. When Chris drove home, there was no traffic and the trip only took
4
hours. If his average rate was
22
miles per hour faster on the trip home, how far away does Chris live from the mountains?
anonymous
 one year ago
Chris drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took 6 hours. When Chris drove home, there was no traffic and the trip only took 4 hours. If his average rate was 22 miles per hour faster on the trip home, how far away does Chris live from the mountains?

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madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0Keisha drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took 8 hours. When Keisha drove home, there was no traffic and the trip only took 6 hours. If her average rate was 16 miles per hour faster on the trip home, how far away does Keisha live from the mountains? way up distance from home = x speed = y time =8 hours d=rt x=8y x8y=0...............(1) return distance =x speed = y+16 time = 6 hours x=6(y+16) x=6y+96 x6y=96...............(2) x 8 y = 0 .............1

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0x 6 y = 96 .............2 Eliminate y multiply (1)by 6 Multiply (2) by 8 6 x 48 y = 0 8 x 48 y = 768 Add the two equations 14 x = 768 / 14 x = 55 plug value of x in (1) 1 x 8 y = 0 55 8 y = 0 8 y = 0 55 8 y = 55 y = 7 x= 55 the distance from home

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0this is an example of the sum you posted now pls try on ur own
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