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\[\frac{ 4 }{ t-2 } - \frac{ 8 }{ t ^{2} -2t} = -2\]

help pls

i beg

first step take lcm of the denominators

what do you get

is the lcm t-2(t^2-2t)

and then i multiple that to the numerators

good

thankss i think im good from there on :)

then what do you get

oh im still up to that step lol, i had trouble finding lcd

you need help

it will come to 4t^2-16t+16/(t-2)(t^2-2t)=-2

hey how far did you go

my answer came out weird

why?

I multiplied the LCD by the numerators but instead of 4t^2-16t+16 i got 4t^2-16t+8

|dw:1441777449360:dw|

this is the first fraction

oh wait i got 4t^2+16t-16 now

good

4t^2+16t-16=-2

where did the denominator go

it was canceled out by the lcd

no i told you what it would be like check my previous 6 th post

4t^2-16t+16/(t-2)(t^2-2t)=-2

doesnt the denominator get canceled out by the lcd when multiplying the numerator?

|dw:1441777787854:dw|

i was taught this way by my teacher

you will get 2[(t-2)(t^2-2t)]=4t^2-16t+16
cross multiply

no baby you were taught wrong

one thing you can do to simplify your equation

you know how to do middle term breaking?

no i have never heard of that

but without mid term this would be difficult

this problem is the hardest problem on my homework :(

will you be able to learn mid term if i teach you

I will try but Im a slow math learner

But lately my teacher use only lcd but this question is weird

http://www.ask-math.com/quadratic-factorization-using-splitting-of-middle-term.html

go to this page and see what you can understand

okay

didi you understand anything

hey i've got another easy way of solving this,do you need it

now you know the formula-(a-b)^2
a^2-2ab+b^2

so now (t-2)^2=t^2-4t+4

so now we can write|dw:1441780923538:dw|

|dw:1441780968546:dw|

by cross multiplying we get|dw:1441781055816:dw|

this is again a quadratic equation and now you got to do mid term breaking

|dw:1441781481309:dw|

so now |dw:1441781642659:dw|