find y ' if ((x^2)(y)) + (sec(y)) = 8

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find y ' if ((x^2)(y)) + (sec(y)) = 8

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Implicit? :) Ooo these are fun!
is this right ? y'(2x + secy tany) = 0
Hmmm no

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im assuming not but i dont know where i went wrong
Did you forget to `product rule` on the first term?
:D yes i did thank you
Ah you silly billy :d
:P okay how about now 2xy + x^2y'+ y' secy tany = 0
Mmm k looks better! :) Now solve for y', ya?
okay sorry my computer keeps overheating , anyway im getting (-2xy)/(x^2 + secy tany)
yay good job \c:/
overheating? 0_o oh my

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