A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
Help:
If a circle has a circumference of C, what is the area of the circle in terms of C?
A=πC
A=C2/4π
A=2C/π
A=2C2
anonymous
 one year ago
Help: If a circle has a circumference of C, what is the area of the circle in terms of C? A=πC A=C2/4π A=2C/π A=2C2

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i dnt know i have a feeling its C but im not quite shure @Rushwr

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\sf C=2\pi r\]\[\sf A=\pi r^2\]If we use our equation of circumference and solve for r, we wcan input that into our equation for Area to set it in terms of C \[\sf C = 2\pi r \implies r = \frac{C}{2\pi}\]\[\sf A= \pi\left(\frac{C}{2\pi}\right)^2\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Now let's expand our function of Area. \[\sf A =\cancel{ \pi} \left(\frac{C^2}{4 \cancel{\pi^2}\pi}\right)\]\[\sf \boxed{A = \frac{C^2}{4\pi}}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Do you follow, @bruno101 ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes i see it seems a little complicated but once u follow its easier @Jhannybean

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0When they say `in terms of C` they want the function (Area) in terms of Circumference. So basically... \(A(\text{circumference})\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0OK I SEE THANKS!! @Jhannybean
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.