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what is x

So, how would I solve this? Would i substitute y=-x+7 into the second equation?

yes

yes do the substitution and solve for x

with the calculated value for x then put in either original to find y

solving the system means you are finding the (x, y) set that satisfies both equation

yes

Okay. I ended up with y=-0.5({-x+7}-3)^2+8. Is that correct?

yes tht is correct

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@Dancingnerd can you continue?

Um. I think so. Then, do i just solve from here?

I ended up with x = -0.5x^2.. It doesn't seem right.

@Dancingnerd do you understand why your expression was wrong?

Oh. It should be x = 0.5x^2.

Yes.

really? how will that give you the value for x ? did you compute that fast?

What do you mean? I think I confused myself.

what equation did you use?

I used -x+7=-0.5(x-3)^2+8.

correct equation

Okay, so how do I solve?

start with the right hand side expand the "exponents" then parenthesis

simplify you will get a quadratic to factor

-x+7=-0.5*x^2+9+8

I have x = 7, x = 1
then find the corresponding values for y

(7, 0) and (-1,6) are the points. Is that correct?

no I have x = 1

That's what I meant. That was the answer that I got.

Thank you so much! I would have never been able to solve that myself.

any questions ?

I'm still a bit unsure how you got x=7 and x = 1.

*did

Ah. Okay.

I think that was where I messed up.

do you understand the process? will you be able to do one by yourself now?