anonymous
  • anonymous
Free medal, lolz simple question. Cow+Bull=?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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LoganH
  • LoganH
Cow
anonymous
  • anonymous
Wrong, try again
LoganH
  • LoganH
longhorn?

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More answers

anonymous
  • anonymous
x3 what r de babies called.
LoganH
  • LoganH
calf
anonymous
  • anonymous
Yay x3
LoganH
  • LoganH
lol
LoganH
  • LoganH
plural calves?
anonymous
  • anonymous
I do this out of randomness
LoganH
  • LoganH
QUICK! what is 13-5*2?
anonymous
  • anonymous
Pemdas!
LoganH
  • LoganH
YAY!
LoganH
  • LoganH
:D
anonymous
  • anonymous
x3 do I win?
LoganH
  • LoganH
what is the square root of calf
LoganH
  • LoganH
idku
idku
  • idku
Suppose that there is such a vector X, that: \(\Large \vec{X}=\vec{\rm Cow}+\vec{\rm Bull}\) And suppose that \(\Large \vec{\rm Cow}\) and \(\Large \vec{\rm Bull}\) are two vertical and horizontal velocity components respectively.
anonymous
  • anonymous
meat
LoganH
  • LoganH
Dear god
LoganH
  • LoganH
idku XD
LoganH
  • LoganH
I have to undo my best response XD
anonymous
  • anonymous
lol
idku
  • idku
So, you can conclude that: \(\Large \vec{\rm Cow}=\vec{X}\cos(\theta)\) \(\Large \vec{\rm Bull}=\vec{X}\sin(\theta)\)
anonymous
  • anonymous
Lol sin
idku
  • idku
So, \(\Large \vec{\rm X}=\vec{X}\cos(\theta)+\vec{X}\sin(\theta)\)
LoganH
  • LoganH
Hmm, enlightenment
idku
  • idku
So if I wanted to find the angle: \(\Large \vec{\rm X}=\vec{X}\cos(\theta)+\vec{X}\sin(\theta)\) \(\Large 1=\cos(\theta)+\sin(\theta)\) \(\Large 1=\cos(\theta)+\sqrt{1-\cos^2(\theta)}\) \(\Large 1-\cos(\theta)=\sqrt{1-\cos^2(\theta)}\) \(\Large 1-2\cos(\theta)+\cos^2(\theta)=1-\cos^2(\theta)\) then, \(\Large 2\cos^2(\theta)=2\cos(\theta)\)
LoganH
  • LoganH
But what if \[\sin (\theta) \int\limits_{bull}^{cow}\xi \Theta _{1}^{cow*bull}\]
LoganH
  • LoganH
changes completely
idku
  • idku
So either \(\cos\theta=0\) or \(\cos(\theta )\)
idku
  • idku
i meant cos theta is 1 for the second option
LoganH
  • LoganH
But look
idku
  • idku
hey, why do you have a a reimann zeta function in it:)
idku
  • idku
|dw:1441818273057:dw|defined for x greater than 1 only
LoganH
  • LoganH
\[\cos 1bull ^{2}if \sum_{cow}^{bull}\left\{ cow*bull \right\}\]
idku
  • idku
ajnd you forgot the differential in your integral LOL
LoganH
  • LoganH
OH! of course! :D
LoganH
  • LoganH
because \[cow \approx bull\]
LoganH
  • LoganH
but \[cow+bull \neq cow+cow\]
idku
  • idku
we know that shi(t) - shi(t)=0 (which is true for shi(t) just like for any number) So, this is what we can do: bull = bull bull = bull + 0 bull = bull + shi(t) - shi(t) bull = bullshi.t - shi.t bull+shi.t=bullshi.t And the: \(\displaystyle\lim_{n\rightarrow \infty}\left(b.u.l.l.s.h.i.t\right)^n\) diverge to infinity
idku
  • idku
and same if you have \(\displaystyle\lim_{n\rightarrow \infty}\left(b.u.l.l{~~+~~}s.h.i.t\right)^n\) diverge to infinity
idku
  • idku
but the bullshi.t one will diverge quicker than the bull+shi.t
LoganH
  • LoganH
hmm, but how do you solve for angle 1? of bullshi(t)
idku
  • idku
We solved theta to be 1....with this condition vector cow and vector give a sum of vector X - initial speed. But if we added pellet to each in direction of each: Such that: \(\Large \vec{XShit}\ne\vec{\rm Cow+Shit}+\vec{\rm Bull+Shit}\)
idku
  • idku
pellet = shi.t
LoganH
  • LoganH
i would think that angle 1 would be congruent with pellet. am I correct?
LoganH
  • LoganH
as \[pellet=shi.t so \angle 1 \neq \angle bull\]
idku
  • idku
Why?
idku
  • idku
well it is not an angle of 1 really, rather cos(\(\theta\))=1 or 0
LoganH
  • LoganH
Because \[Bullshi.t ^{2^{cow}}+bull=cow*copulation\]
idku
  • idku
So, \(\pi/2\) or \(\pi\)
idku
  • idku
And at that angle only is it true thatSuppose that there is such a vector X, that: \(\Large \vec{\rm Cow}\) = \(\Large \vec{\rm Bull}\)
LoganH
  • LoganH
But, would we also consider the size of said bull? because \[bull21 \neq bull 13\]
idku
  • idku
And thus follows that: \(\Large \rm CowShi.t\) = \(\Large\rm BullShi.t\) and since both sides are equivalent you can remove the vectors as I did.
idku
  • idku
yes, true, because bull\(\ne\)=0
LoganH
  • LoganH
|dw:1441819171326:dw|
idku
  • idku
And \(\large {shi.t}=\displaystyle \int x^{shi.t~~-1}e^{-x}dx=\Gamma({shi.t})\)
idku
  • idku
so pellet=1
LoganH
  • LoganH
There we go
LoganH
  • LoganH
and pellet=shi.t right?
idku
  • idku
Nice
idku
  • idku
pellet is shi.t
idku
  • idku
I have to go now... se you
LoganH
  • LoganH
So we have solved it?
LoganH
  • LoganH
Thanks! :D

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