## anonymous one year ago Free medal, lolz simple question. Cow+Bull=?

1. LoganH

Cow

2. anonymous

Wrong, try again

3. LoganH

longhorn?

4. anonymous

x3 what r de babies called.

5. LoganH

calf

6. anonymous

Yay x3

7. LoganH

lol

8. LoganH

plural calves?

9. anonymous

I do this out of randomness

10. LoganH

QUICK! what is 13-5*2?

11. anonymous

Pemdas!

12. LoganH

YAY!

13. LoganH

:D

14. anonymous

x3 do I win?

15. LoganH

what is the square root of calf

16. LoganH

idku

17. idku

Suppose that there is such a vector X, that: $$\Large \vec{X}=\vec{\rm Cow}+\vec{\rm Bull}$$ And suppose that $$\Large \vec{\rm Cow}$$ and $$\Large \vec{\rm Bull}$$ are two vertical and horizontal velocity components respectively.

18. anonymous

meat

19. LoganH

Dear god

20. LoganH

idku XD

21. LoganH

I have to undo my best response XD

22. anonymous

lol

23. idku

So, you can conclude that: $$\Large \vec{\rm Cow}=\vec{X}\cos(\theta)$$ $$\Large \vec{\rm Bull}=\vec{X}\sin(\theta)$$

24. anonymous

Lol sin

25. idku

So, $$\Large \vec{\rm X}=\vec{X}\cos(\theta)+\vec{X}\sin(\theta)$$

26. LoganH

Hmm, enlightenment

27. idku

So if I wanted to find the angle: $$\Large \vec{\rm X}=\vec{X}\cos(\theta)+\vec{X}\sin(\theta)$$ $$\Large 1=\cos(\theta)+\sin(\theta)$$ $$\Large 1=\cos(\theta)+\sqrt{1-\cos^2(\theta)}$$ $$\Large 1-\cos(\theta)=\sqrt{1-\cos^2(\theta)}$$ $$\Large 1-2\cos(\theta)+\cos^2(\theta)=1-\cos^2(\theta)$$ then, $$\Large 2\cos^2(\theta)=2\cos(\theta)$$

28. LoganH

But what if $\sin (\theta) \int\limits_{bull}^{cow}\xi \Theta _{1}^{cow*bull}$

29. LoganH

changes completely

30. idku

So either $$\cos\theta=0$$ or $$\cos(\theta )$$

31. idku

i meant cos theta is 1 for the second option

32. LoganH

But look

33. idku

hey, why do you have a a reimann zeta function in it:)

34. idku

|dw:1441818273057:dw|defined for x greater than 1 only

35. LoganH

$\cos 1bull ^{2}if \sum_{cow}^{bull}\left\{ cow*bull \right\}$

36. idku

ajnd you forgot the differential in your integral LOL

37. LoganH

OH! of course! :D

38. LoganH

because $cow \approx bull$

39. LoganH

but $cow+bull \neq cow+cow$

40. idku

we know that shi(t) - shi(t)=0 (which is true for shi(t) just like for any number) So, this is what we can do: bull = bull bull = bull + 0 bull = bull + shi(t) - shi(t) bull = bullshi.t - shi.t bull+shi.t=bullshi.t And the: $$\displaystyle\lim_{n\rightarrow \infty}\left(b.u.l.l.s.h.i.t\right)^n$$ diverge to infinity

41. idku

and same if you have $$\displaystyle\lim_{n\rightarrow \infty}\left(b.u.l.l{~~+~~}s.h.i.t\right)^n$$ diverge to infinity

42. idku

but the bullshi.t one will diverge quicker than the bull+shi.t

43. LoganH

hmm, but how do you solve for angle 1? of bullshi(t)

44. idku

We solved theta to be 1....with this condition vector cow and vector give a sum of vector X - initial speed. But if we added pellet to each in direction of each: Such that: $$\Large \vec{Xpellet}\ne\vec{\rm Cow+pellet}+\vec{\rm Bull+pellet}$$

45. idku

pellet = shi.t

46. LoganH

i would think that angle 1 would be congruent with pellet. am I correct?

47. LoganH

as $pellet=shi.t so \angle 1 \neq \angle bull$

48. idku

Why?

49. idku

well it is not an angle of 1 really, rather cos($$\theta$$)=1 or 0

50. LoganH

Because $Bullshi.t ^{2^{cow}}+bull=cow*copulation$

51. idku

So, $$\pi/2$$ or $$\pi$$

52. idku

And at that angle only is it true thatSuppose that there is such a vector X, that: $$\Large \vec{\rm Cow}$$ = $$\Large \vec{\rm Bull}$$

53. LoganH

But, would we also consider the size of said bull? because $bull21 \neq bull 13$

54. idku

And thus follows that: $$\Large \rm CowShi.t$$ = $$\Large\rm BullShi.t$$ and since both sides are equivalent you can remove the vectors as I did.

55. idku

yes, true, because bull$$\ne$$=0

56. LoganH

|dw:1441819171326:dw|

57. idku

And $$\large {shi.t}=\displaystyle \int x^{shi.t~~-1}e^{-x}dx=\Gamma({shi.t})$$

58. idku

so pellet=1

59. LoganH

There we go

60. LoganH

and pellet=shi.t right?

61. idku

Nice

62. idku

pellet is shi.t

63. idku

I have to go now... se you

64. LoganH

So we have solved it?

65. LoganH

Thanks! :D