## anonymous one year ago An electron in a cathode-ray-tube (CRT) accelerates uniformly from 5.00 ✕ 104 m/s to 6.00 ✕ 106 m/s over 3.00 cm. (a) In what time interval does the electron travel this 3.00 cm? (b) What is its acceleration?

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1. IrishBoy123

i would do these in reverse using the equation of motion $$v^2 = u^2 + 2ax$$ will give you the acceleration, a, with least fuss using the equation of motion $$v = u + at$$ will give you the time, t the 3 basic equations l are 1. $v = u + at$ 2.$x = ut + \frac{1}{2}at^2$ 3.$v^2 = u^2 + 2ax$