## Pagen13 one year ago Can someone help me with a few questions??! I have issues with slope!

1. kropot72

Can you post one of the questions.

2. Pagen13

What is the slope of the line that passes through the given points? (3,2) and (5,12) a. 5 b. -5 c. -1/5 d. 1/5

3. hartnn

The slope of the line through points (x1,y1) and (x2,y2) is given by : $$\huge m=\frac{y_1-y_2}{x_1-x_2}$$ now,just put the values and find m.

4. hartnn

in your question, x1= 3 y1 = 2 x2 =5 y2 =12

5. Pagen13

so 2-12/3-5

6. hartnn

yes don't forget the brackets (2-12)/(3-5)

7. Pagen13

-10/-2=5

8. hartnn

good! $$\huge \checkmark$$

9. Pagen13

Can you help with some more?

10. hartnn

sure :)

11. Pagen13

What is the graph of the equation? 2x-y=2

12. hartnn

it would be a line. to get the intercepts of that line plug in x= 0, find y plug in y= 0 find x

13. Pagen13

14. Pagen13

How do I plug it in? Sorry I am lost..

15. hartnn

2x- y =2 to get x intercept, we put y =0 2x = 2 x =1 so x intercept is 1,0 can you now find y intercept ? put x= 0 in 2x-y =2

16. Pagen13

y=0

17. hartnn

-y = 2 so y =-2 y intercept is 0,-2

18. hartnn

now the points 1,0 and 0,-2 should lie on the graph. which graph has these 2 points?

19. Pagen13

C

20. hartnn

correct :)

21. Pagen13

Write an equation of the line, in point slope form that passes through the two given points: (-2,15) and (9,-18) a.y-2=-3(x-15) b.y-2=-1/3(x+15) c.y-15=-3(x+2) d.y-15=-1/3(x+2)

22. hartnn

first find the slope using the above formula. x1 = -2 y1 = 15 x2 = 9 y2 = -18

23. Pagen13

-11/33=3

24. hartnn

-11/33 is -1/3

25. Pagen13

Oh yeah sorry..

26. hartnn

so the equation would be y-y1 = m (x-x1) y -15 = -1/3 (x+2)

27. Pagen13

Thank you! I have 8 more can you help? I am starting to understand!