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anonymous
 one year ago
The limit of (2+x)/(1x) as x approaches 1 from the right? Help please?
anonymous
 one year ago
The limit of (2+x)/(1x) as x approaches 1 from the right? Help please?

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beginnersmind
 one year ago
Best ResponseYou've already chosen the best response.1Try sketching it. And think about what happens to the fraction as x gets close to 1. Use a calculator to calculte some values, like at x = 1.1 or x = 1.01.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I have to do it on paper without my calculator or graphing paper. Simply through math. ..

beginnersmind
 one year ago
Best ResponseYou've already chosen the best response.1Ok, but it still helps to know what the answer is "before" doing the math.

beginnersmind
 one year ago
Best ResponseYou've already chosen the best response.1You go from "How do I this?" to "I know what the answer is, now how do I justify it?" The second is much easier.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I know it's negative infinity. I just don't understand how the answer is that.

beginnersmind
 one year ago
Best ResponseYou've already chosen the best response.1Ok, cool. Why is it negative infinity. What happens to the numerator and the denominator near 1?

beginnersmind
 one year ago
Best ResponseYou've already chosen the best response.1What's lim(x+2) and lim(1x) at x=1

beginnersmind
 one year ago
Best ResponseYou've already chosen the best response.1Right. So the limit is 3/0. That's either + or  infinity, depending on whether the denominator goes to zero through positive or negative numbers.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but 3//0 is undefined. The graph has a hole at 1 and becomes asymptotic on the yaxis.

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.0Another way to think about it logically is to start similarly to how beginners initially said with 1.1 and 1.01, but with easier numbers. You are coming in from the right, so numbers larger than 1. Say 3. (2+3)/(13) = 5/2. Then 2, so 4. Then look at it logically. You have negative numbers where the numerator is getting what and denominator is getting what? Larger? Smaller? Is it going to change from negative to positive and if so, when?

beginnersmind
 one year ago
Best ResponseYou've already chosen the best response.1"but 3//0 is undefined. The graph has a hole at 1 and becomes asymptotic on the yaxis." Indeed, 3/0 is undefined for numbers. But for limits it makes sense. The function isn't defined at x = 1. But it is defined for 1.1, 1.01, 1.001, etc. When we say that the limit is minus infinity we're just saying that the value of the expression is arbitrarily small, as long as we are close enough to x=1. Another way to say that is that the graph has an asymptote at x=1.

beginnersmind
 one year ago
Best ResponseYou've already chosen the best response.1No problem. Hope I managed to make it a little clearer at least.

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.0A limit is not where you are at but where you are heading. That is where my logically comment comes in. Again, to tie it to the very good explanation by beginners, this line is travelling down the x numbers pretty rapidly from say 100 to about 4, but the y numbers travele slowly. From x=4 to x=2, the x and y change at about the same speed. Below x=2, the x is changing very slow in comparison to how fast the y is changing. Then, it venetially hits x=1 where it is, as you pointed out perfectly, undefined. So the limit is headding to something undefined. In this case, that particular undefined is negative infinity. That is why it makes sense for a limit. You are heading to the undefined value of negative infinity. You can't define it close than that.
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