FInd sin55 using ratios of sides of the given triangle. Check using calculator

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FInd sin55 using ratios of sides of the given triangle. Check using calculator

Mathematics
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sin(55) is opposite/hyp
well opposite side of that angle with measure 55 deg/hyp of the triangle
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I solved for both a and b and got a= 20.48 b= 14.34
ok and I guess you rounded to the nearest hundredth a is correct
checking b
that is also correct
okay so to set up the problem it would be sin(55)=14.34/25 right?
didn't you already solve the problem?
also how could sin(55) be 14.34/25 when it was sin(55)=a/25 and you got a to be 20.48?
I guess I am confused. Because I found a and b and then it is asking me to find sin55.. but i tested ratios of sides and everthing comes out false
well you solved sin(55)=a/25 for a correct?
and you got a to be 20.48?
so sin(55)=20.48/25
oh gotcha! that makes way more sense so the ratio was just that
yes replace a with what it equals not what b equals :p
\[\sin(35)=\frac{b}{25} \\ \text{ so you could say } \sin(35)=\frac{14.34}{25}\]
just if they asked you to do sin(35)
notice I replaced b with 14.34 since that is what you found b to be

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