Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

See more answers at brainly.com

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions

yep that's what it's supposed to be

scan or link the question pls

sorry, been here done that!
just scan or link it :p

the one you typed is the correct one

scan or link your question
no point is answering to ghosts

\[\sqrt[4]{x^2+2x}\]

what happens if you have this\[\sqrt[4]{-1}\]?
does this exist over the real numbers?

I don't think so since you shouldnt have -'s under a radical

great so you want x^2+2x to be positive or zero right?

yeah

for a number to be positive or equal it must be greater than or equal to 0

so you basically need to solve x^2+2x>=0

to find the domain

do we just get rid of the radical then?

the thing under the radical was x^2+2x

so you want x^2+2x>=0

it has to be in interval notation

so would I start with (0,_)

you would solve x^2+2x>=0

then we can put an interval notation

x^2>or= -2x

and then would we square both sides?? because then there'd be a negative on the right

|dw:1441829210139:dw|

OHH so x can equal 0 or -2?

can;t*

3,-1, and 3?

|dw:1441829448997:dw|

so this tells us x^2+2x is positive on the first and last intervals

in this number line

|dw:1441829505021:dw|

(-infinity,-2)U(-2,0)U(-2,0)U(0,infinity)?

you need to include both -2 and 0...
also why are you include (-2,0)
x^2+2x is negative on (-2,0)

remember we were trying to find x such that x^2+2x was positive or zero

no I don't :-(

|dw:1441829916519:dw|

|dw:1441830041033:dw|

oh, so we dont include -2,0 because it would result in a negative

okay so we include those but not (-2,0)

so how would I write that in interval notationn without including (-2,0)