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anonymous
 one year ago
Find the domain of the function.
g(x)=^4sq.rt x^2+2x
anonymous
 one year ago
Find the domain of the function. g(x)=^4sq.rt x^2+2x

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yep that's what it's supposed to be

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0scan or link the question pls

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0sorry, been here done that! just scan or link it :p

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the one you typed is the correct one

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0scan or link your question no point is answering to ghosts

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i don't know how to scan it and the link wont work since it's under my account name.. you already know what the problem looks like, you sent it yourself, so it should be good enough?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\sqrt[4]{x^2+2x}\]

freckles
 one year ago
Best ResponseYou've already chosen the best response.1what happens if you have this\[\sqrt[4]{1}\]? does this exist over the real numbers?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I don't think so since you shouldnt have 's under a radical

freckles
 one year ago
Best ResponseYou've already chosen the best response.1great so you want x^2+2x to be positive or zero right?

freckles
 one year ago
Best ResponseYou've already chosen the best response.1for a number to be positive or equal it must be greater than or equal to 0

freckles
 one year ago
Best ResponseYou've already chosen the best response.1so you basically need to solve x^2+2x>=0

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do we just get rid of the radical then?

freckles
 one year ago
Best ResponseYou've already chosen the best response.1you told me just a sec ago that we didn't want the thing under the radical to be negative which means we want it to be zero or positive

freckles
 one year ago
Best ResponseYou've already chosen the best response.1the thing under the radical was x^2+2x

freckles
 one year ago
Best ResponseYou've already chosen the best response.1so you want x^2+2x>=0

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it has to be in interval notation

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so would I start with (0,_)

freckles
 one year ago
Best ResponseYou've already chosen the best response.1you would solve x^2+2x>=0

freckles
 one year ago
Best ResponseYou've already chosen the best response.1then we can put an interval notation

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and then would we square both sides?? because then there'd be a negative on the right

freckles
 one year ago
Best ResponseYou've already chosen the best response.1\[x^2+2x \ge 0 \\ x(x+2) \ge 0\] draw a number line x(x+2) is zero when x=0 or x+2=0 dw:1441829182423:dw test the intervals

freckles
 one year ago
Best ResponseYou've already chosen the best response.1dw:1441829210139:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0OHH so x can equal 0 or 2?

freckles
 one year ago
Best ResponseYou've already chosen the best response.1let me know when you have tested the intervals and yes x=2 and x=0 will be included in the solution for the domain but we have to also consider the numbers around them

freckles
 one year ago
Best ResponseYou've already chosen the best response.1dw:1441829448997:dw

freckles
 one year ago
Best ResponseYou've already chosen the best response.1so this tells us x^2+2x is positive on the first and last intervals

freckles
 one year ago
Best ResponseYou've already chosen the best response.1dw:1441829505021:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(infinity,2)U(2,0)U(2,0)U(0,infinity)?

freckles
 one year ago
Best ResponseYou've already chosen the best response.1you need to include both 2 and 0... also why are you include (2,0) x^2+2x is negative on (2,0)

freckles
 one year ago
Best ResponseYou've already chosen the best response.1remember we were trying to find x such that x^2+2x was positive or zero

freckles
 one year ago
Best ResponseYou've already chosen the best response.1we found x^2+2x was zero at x=2, x=0 we found x^2+2x was positive for values to the left of 2, also values to right of 0

freckles
 one year ago
Best ResponseYou've already chosen the best response.1you should not include (2,0) do you understand why? you should include 2 and 0 in your solution do you understand this also?

freckles
 one year ago
Best ResponseYou've already chosen the best response.1hmm... so do you remember when we tested the intervals earlier and for the member that represented the set of numbers on (2,0) we got a negative number?

freckles
 one year ago
Best ResponseYou've already chosen the best response.1dw:1441829916519:dw

freckles
 one year ago
Best ResponseYou've already chosen the best response.1dw:1441829938691:dw I put check marks on the intervals we want because we were looking for intervals where x^2+2x was positive I put an X mark on intervals we don't want because we were not looking for when x^2+2x was negative.

freckles
 one year ago
Best ResponseYou've already chosen the best response.1the 4 root of 0 exists and it is 0 so x^2+2x=0 will satisfy our domain x(x+2)=0 when x=0 and x=2 these numbers have to be a part of the domain

freckles
 one year ago
Best ResponseYou've already chosen the best response.1dw:1441830041033:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh, so we dont include 2,0 because it would result in a negative

freckles
 one year ago
Best ResponseYou've already chosen the best response.1no we don't include (2,0) because any number from that set would result in a negative we do include 2 and 0 though because pluggin in those numbers result in zero

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay so we include those but not (2,0)

freckles
 one year ago
Best ResponseYou've already chosen the best response.1yes any number from (2,0) when pluggin in to x^2+2x will give you a negative number you have already said the 4th root of a negative number doesn't exist over the real numbers

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so how would I write that in interval notationn without including (2,0)
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