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cutiecomittee123

  • one year ago

Find sin x and csc y First of all how do use csc on a calculator (if possible) of all how in the world do I set up the equations to solve? I know that sin is opposite over hypotenuse and csc is hypotenuse over opposite

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  1. cutiecomittee123
    • one year ago
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    |dw:1441828737649:dw|

  2. Nnesha
    • one year ago
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    csc is reciprocal of 1/sin sec is reciprocal of 1/cos cot is reciprocal of 1/tan

  3. cutiecomittee123
    • one year ago
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    makes sense. so then to solve for sinx sinx=5/a

  4. cutiecomittee123
    • one year ago
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    right?

  5. Nnesha
    • one year ago
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    first ) apply the Pythagorean theorem to find 3rd side of right triangle \[\huge\rm a^2+b^2=c^2\]

  6. Nnesha
    • one year ago
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    yes right but first find c (hypotenuse ) let hypotenuse = c

  7. cutiecomittee123
    • one year ago
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    okay so 25+49=74

  8. cutiecomittee123
    • one year ago
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    and the sqrt of 74 is the hypotenuse

  9. Nnesha
    • one year ago
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    yes right that is c^2 but we need c

  10. Nnesha
    • one year ago
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    yes right

  11. Nnesha
    • one year ago
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    \(\color{blue}{\text{Originally Posted by}}\) @cutiecomittee123 makes sense. so then to solve for sinx sinx=5/a \(\color{blue}{\text{End of Quote}}\) now substitute a for sqrt{74}

  12. cutiecomittee123
    • one year ago
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    which is 8.6

  13. cutiecomittee123
    • one year ago
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    do i keep it sin(x)=5/sqrt74 or do i simplify

  14. cutiecomittee123
    • one year ago
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    okay

  15. Nnesha
    • one year ago
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    yes simplify solve for x

  16. cutiecomittee123
    • one year ago
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    i get a crazy weird number when i try to calculate that

  17. Nnesha
    • one year ago
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    what did you get ? first of all your calculator mode should be on degree 2nd you should take invs sin

  18. Nnesha
    • one year ago
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    understand ? ?//

  19. cutiecomittee123
    • one year ago
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    okay hold on

  20. cutiecomittee123
    • one year ago
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    i get sinx=.0011792563

  21. Nnesha
    • one year ago
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    when we have to find an angle then we should use `invs sin` \[x = \sin^{-1} \frac{ 5 }{ 8.6 }\]

  22. Nnesha
    • one year ago
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    or in other words `arcsin` http://prntscr.com/8eiznl

  23. cutiecomittee123
    • one year ago
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    okay so you just keep it that way, no more simplifying?

  24. Nnesha
    • one year ago
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    no use calculator to find x \[x = \sin^{-1} \frac{ 5 }{ 8.6 }\]

  25. cutiecomittee123
    • one year ago
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    alright so x=8.6

  26. cutiecomittee123
    • one year ago
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    @Nnesha

  27. Nnesha
    • one year ago
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    hmm not x isn't 8.6 the hypotenuse = 8.6

  28. Nnesha
    • one year ago
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    |dw:1441834691882:dw|

  29. Nnesha
    • one year ago
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    type this into the calculator \[ \sin^{-1} \frac{ 5 }{ 8.6 }\]

  30. cutiecomittee123
    • one year ago
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    I did

  31. cutiecomittee123
    • one year ago
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    it gave me 8.6

  32. cutiecomittee123
    • one year ago
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    wait no it gives me .0011792563

  33. Nnesha
    • one year ago
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    hmm not sure how u got that what did you type into the calculator ?

  34. cutiecomittee123
    • one year ago
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    i typed x^-1 before then sin(5/8.6)

  35. Nnesha
    • one year ago
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    it's sin^{-1} not x^{-1} arcsin =sin^{-1}

  36. cutiecomittee123
    • one year ago
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    okay so 98.55

  37. cutiecomittee123
    • one year ago
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    that is what i get when i put the inverse second after the other part of the equation

  38. Nnesha
    • one year ago
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    on ti-84 calculator ?

  39. cutiecomittee123
    • one year ago
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    yeah

  40. cutiecomittee123
    • one year ago
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    x^-1 is inverse

  41. Nnesha
    • one year ago
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    for that calculator press `2nd-sin` then type (5/8.6)

  42. cutiecomittee123
    • one year ago
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    Ahh I see, way more acurate answer. x=35.55

  43. Nnesha
    • one year ago
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    got it !

  44. Nnesha
    • one year ago
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    that's right !

  45. cutiecomittee123
    • one year ago
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    okay and then we have to find the csc of y, an you help

  46. cutiecomittee123
    • one year ago
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    can*

  47. Nnesha
    • one year ago
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    i'll use the fact that all triangles add up to 180 degree so it's right triangle so one angle 90 other angle we just found 35.5 i don't knw why sin (x)= 8.6/7 gives me error on calculator

  48. cutiecomittee123
    • one year ago
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    y=54.5

  49. Nnesha
    • one year ago
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    yes right

  50. cutiecomittee123
    • one year ago
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    alright, i dont know if you still want to help but there are two more and i think i have the hang of it, but it is always nice to have a little help:) find tan c and cot y and find cos x and sec y

  51. Nnesha
    • one year ago
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    geez i don't know why it csc y giving me an error anyways \[\huge\rm csc( x )=\frac{ 8.6 }{ 7 }\] then find inverse csc

  52. cutiecomittee123
    • one year ago
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    there is no csc button

  53. Nnesha
    • one year ago
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    with same triangle ?

  54. Nnesha
    • one year ago
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    i know but csc = 1/sin so it should be i /sin^{-1}(7/8.6)

  55. cutiecomittee123
    • one year ago
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    yes same triangle Okay let me try that

  56. cutiecomittee123
    • one year ago
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    so plug in 1/sin(-1) (7/8.6) ????

  57. Nnesha
    • one year ago
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    welll i plugged in sin^{-1} (7/8.6) i got 54.48

  58. Nnesha
    • one year ago
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    still don't understand anyways move to the next one

  59. cutiecomittee123
    • one year ago
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    waiiiiittt, are we still working on the first problem to find csc(y)? because i got the same answer y=54.5 because i just used your advice that there are 180 degrees in a triangle and we already have 90+35.5 and then i subtracted them from 180 and got 54.5 as well. I think that is the right answer

  60. Nnesha
    • one year ago
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    yes that's the right answer but i was trying to find how to find csc y without using the fact 180 degree :D

  61. Nnesha
    • one year ago
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    \(\color{blue}{\text{Originally Posted by}}\) @cutiecomittee123 alright, i dont know if you still want to help but there are two more and i think i have the hang of it, but it is always nice to have a little help:) find `tan c` and cot y and find cos x and sec y \(\color{blue}{\text{End of Quote}}\) do you mean `tan x` ???

  62. cutiecomittee123
    • one year ago
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    yes tan x

  63. Nnesha
    • one year ago
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    alright try it first remember cot is reciprocal of tan

  64. cutiecomittee123
    • one year ago
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    well tan(x)=5/7

  65. Nnesha
    • one year ago
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    right solve for x !

  66. cutiecomittee123
    • one year ago
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    Okay so I would just multiply by 7 on each side and that makes it 7tan(x)=35

  67. Nnesha
    • one year ago
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    well you don't have to multiply by 7 just take the invs tan and then calculator

  68. cutiecomittee123
    • one year ago
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    okay so i did 2nd, tan(5/7) and i got 35.54

  69. Nnesha
    • one year ago
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    perfect!

  70. cutiecomittee123
    • one year ago
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    i did it? is that it lol

  71. Nnesha
    • one year ago
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    yes right that's tan x

  72. cutiecomittee123
    • one year ago
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    okay so now to find cot y

  73. cutiecomittee123
    • one year ago
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    wouldnt it just be cot y = 7/5

  74. cutiecomittee123
    • one year ago
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    oh is it just tan(5/7)

  75. Nnesha
    • one year ago
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    tan y = what ?

  76. cutiecomittee123
    • one year ago
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    well it is inverse tan so i figured you use tan when calculating

  77. Nnesha
    • one year ago
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    well you did the opposite tan = opposite over adjacent and cot = adjacent over opposite

  78. cutiecomittee123
    • one year ago
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    so you keep it the way it is but just dont take the iverse? sine we took the inverse to find tan x

  79. cutiecomittee123
    • one year ago
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    inverse since *

  80. Nnesha
    • one year ago
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    guess what i'm so hungry right now i need 2nd opinion on this one i feel like we don't need angle we just write in the form tan x = 7/5 that's it

  81. Nnesha
    • one year ago
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    is it just find sin x or solve for x ?

  82. Nnesha
    • one year ago
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    or like what is x and y ?

  83. Nnesha
    • one year ago
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    \(\color{blue}{\text{Originally Posted by}}\) @cutiecomittee123 wouldnt it just be cot y = 7/5 \(\color{blue}{\text{End of Quote}}\) cot y = 5/7 ( adjacent over opposite) so it would be arctan(7/5)

  84. Nnesha
    • one year ago
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    ye then cos = adjacent over hyp so same concept with sec just like cot i think ur afk

  85. Nnesha
    • one year ago
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    i've to go now.

  86. cutiecomittee123
    • one year ago
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    okay i see. Thanks for your help!!!

  87. Nnesha
    • one year ago
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    yw

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