Find sin x and csc y First of all how do use csc on a calculator (if possible) of all how in the world do I set up the equations to solve? I know that sin is opposite over hypotenuse and csc is hypotenuse over opposite

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Find sin x and csc y First of all how do use csc on a calculator (if possible) of all how in the world do I set up the equations to solve? I know that sin is opposite over hypotenuse and csc is hypotenuse over opposite

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|dw:1441828737649:dw|
csc is reciprocal of 1/sin sec is reciprocal of 1/cos cot is reciprocal of 1/tan
makes sense. so then to solve for sinx sinx=5/a

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Other answers:

right?
first ) apply the Pythagorean theorem to find 3rd side of right triangle \[\huge\rm a^2+b^2=c^2\]
yes right but first find c (hypotenuse ) let hypotenuse = c
okay so 25+49=74
and the sqrt of 74 is the hypotenuse
yes right that is c^2 but we need c
yes right
\(\color{blue}{\text{Originally Posted by}}\) @cutiecomittee123 makes sense. so then to solve for sinx sinx=5/a \(\color{blue}{\text{End of Quote}}\) now substitute a for sqrt{74}
which is 8.6
do i keep it sin(x)=5/sqrt74 or do i simplify
okay
yes simplify solve for x
i get a crazy weird number when i try to calculate that
what did you get ? first of all your calculator mode should be on degree 2nd you should take invs sin
understand ? ?//
okay hold on
i get sinx=.0011792563
when we have to find an angle then we should use `invs sin` \[x = \sin^{-1} \frac{ 5 }{ 8.6 }\]
or in other words `arcsin` http://prntscr.com/8eiznl
okay so you just keep it that way, no more simplifying?
no use calculator to find x \[x = \sin^{-1} \frac{ 5 }{ 8.6 }\]
alright so x=8.6
hmm not x isn't 8.6 the hypotenuse = 8.6
|dw:1441834691882:dw|
type this into the calculator \[ \sin^{-1} \frac{ 5 }{ 8.6 }\]
I did
it gave me 8.6
wait no it gives me .0011792563
hmm not sure how u got that what did you type into the calculator ?
i typed x^-1 before then sin(5/8.6)
it's sin^{-1} not x^{-1} arcsin =sin^{-1}
okay so 98.55
that is what i get when i put the inverse second after the other part of the equation
on ti-84 calculator ?
yeah
x^-1 is inverse
for that calculator press `2nd-sin` then type (5/8.6)
Ahh I see, way more acurate answer. x=35.55
got it !
that's right !
okay and then we have to find the csc of y, an you help
can*
i'll use the fact that all triangles add up to 180 degree so it's right triangle so one angle 90 other angle we just found 35.5 i don't knw why sin (x)= 8.6/7 gives me error on calculator
y=54.5
yes right
alright, i dont know if you still want to help but there are two more and i think i have the hang of it, but it is always nice to have a little help:) find tan c and cot y and find cos x and sec y
geez i don't know why it csc y giving me an error anyways \[\huge\rm csc( x )=\frac{ 8.6 }{ 7 }\] then find inverse csc
there is no csc button
with same triangle ?
i know but csc = 1/sin so it should be i /sin^{-1}(7/8.6)
yes same triangle Okay let me try that
so plug in 1/sin(-1) (7/8.6) ????
welll i plugged in sin^{-1} (7/8.6) i got 54.48
still don't understand anyways move to the next one
waiiiiittt, are we still working on the first problem to find csc(y)? because i got the same answer y=54.5 because i just used your advice that there are 180 degrees in a triangle and we already have 90+35.5 and then i subtracted them from 180 and got 54.5 as well. I think that is the right answer
yes that's the right answer but i was trying to find how to find csc y without using the fact 180 degree :D
\(\color{blue}{\text{Originally Posted by}}\) @cutiecomittee123 alright, i dont know if you still want to help but there are two more and i think i have the hang of it, but it is always nice to have a little help:) find `tan c` and cot y and find cos x and sec y \(\color{blue}{\text{End of Quote}}\) do you mean `tan x` ???
yes tan x
alright try it first remember cot is reciprocal of tan
well tan(x)=5/7
right solve for x !
Okay so I would just multiply by 7 on each side and that makes it 7tan(x)=35
well you don't have to multiply by 7 just take the invs tan and then calculator
okay so i did 2nd, tan(5/7) and i got 35.54
perfect!
i did it? is that it lol
yes right that's tan x
okay so now to find cot y
wouldnt it just be cot y = 7/5
oh is it just tan(5/7)
tan y = what ?
well it is inverse tan so i figured you use tan when calculating
well you did the opposite tan = opposite over adjacent and cot = adjacent over opposite
so you keep it the way it is but just dont take the iverse? sine we took the inverse to find tan x
inverse since *
guess what i'm so hungry right now i need 2nd opinion on this one i feel like we don't need angle we just write in the form tan x = 7/5 that's it
is it just find sin x or solve for x ?
or like what is x and y ?
\(\color{blue}{\text{Originally Posted by}}\) @cutiecomittee123 wouldnt it just be cot y = 7/5 \(\color{blue}{\text{End of Quote}}\) cot y = 5/7 ( adjacent over opposite) so it would be arctan(7/5)
ye then cos = adjacent over hyp so same concept with sec just like cot i think ur afk
i've to go now.
okay i see. Thanks for your help!!!
yw

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