cutiecomittee123
  • cutiecomittee123
Find sin x and csc y First of all how do use csc on a calculator (if possible) of all how in the world do I set up the equations to solve? I know that sin is opposite over hypotenuse and csc is hypotenuse over opposite
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
cutiecomittee123
  • cutiecomittee123
|dw:1441828737649:dw|
Nnesha
  • Nnesha
csc is reciprocal of 1/sin sec is reciprocal of 1/cos cot is reciprocal of 1/tan
cutiecomittee123
  • cutiecomittee123
makes sense. so then to solve for sinx sinx=5/a

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

cutiecomittee123
  • cutiecomittee123
right?
Nnesha
  • Nnesha
first ) apply the Pythagorean theorem to find 3rd side of right triangle \[\huge\rm a^2+b^2=c^2\]
Nnesha
  • Nnesha
yes right but first find c (hypotenuse ) let hypotenuse = c
cutiecomittee123
  • cutiecomittee123
okay so 25+49=74
cutiecomittee123
  • cutiecomittee123
and the sqrt of 74 is the hypotenuse
Nnesha
  • Nnesha
yes right that is c^2 but we need c
Nnesha
  • Nnesha
yes right
Nnesha
  • Nnesha
\(\color{blue}{\text{Originally Posted by}}\) @cutiecomittee123 makes sense. so then to solve for sinx sinx=5/a \(\color{blue}{\text{End of Quote}}\) now substitute a for sqrt{74}
cutiecomittee123
  • cutiecomittee123
which is 8.6
cutiecomittee123
  • cutiecomittee123
do i keep it sin(x)=5/sqrt74 or do i simplify
cutiecomittee123
  • cutiecomittee123
okay
Nnesha
  • Nnesha
yes simplify solve for x
cutiecomittee123
  • cutiecomittee123
i get a crazy weird number when i try to calculate that
Nnesha
  • Nnesha
what did you get ? first of all your calculator mode should be on degree 2nd you should take invs sin
Nnesha
  • Nnesha
understand ? ?//
cutiecomittee123
  • cutiecomittee123
okay hold on
cutiecomittee123
  • cutiecomittee123
i get sinx=.0011792563
Nnesha
  • Nnesha
when we have to find an angle then we should use `invs sin` \[x = \sin^{-1} \frac{ 5 }{ 8.6 }\]
Nnesha
  • Nnesha
or in other words `arcsin` http://prntscr.com/8eiznl
cutiecomittee123
  • cutiecomittee123
okay so you just keep it that way, no more simplifying?
Nnesha
  • Nnesha
no use calculator to find x \[x = \sin^{-1} \frac{ 5 }{ 8.6 }\]
cutiecomittee123
  • cutiecomittee123
alright so x=8.6
cutiecomittee123
  • cutiecomittee123
@Nnesha
Nnesha
  • Nnesha
hmm not x isn't 8.6 the hypotenuse = 8.6
Nnesha
  • Nnesha
|dw:1441834691882:dw|
Nnesha
  • Nnesha
type this into the calculator \[ \sin^{-1} \frac{ 5 }{ 8.6 }\]
cutiecomittee123
  • cutiecomittee123
I did
cutiecomittee123
  • cutiecomittee123
it gave me 8.6
cutiecomittee123
  • cutiecomittee123
wait no it gives me .0011792563
Nnesha
  • Nnesha
hmm not sure how u got that what did you type into the calculator ?
cutiecomittee123
  • cutiecomittee123
i typed x^-1 before then sin(5/8.6)
Nnesha
  • Nnesha
it's sin^{-1} not x^{-1} arcsin =sin^{-1}
cutiecomittee123
  • cutiecomittee123
okay so 98.55
cutiecomittee123
  • cutiecomittee123
that is what i get when i put the inverse second after the other part of the equation
Nnesha
  • Nnesha
on ti-84 calculator ?
cutiecomittee123
  • cutiecomittee123
yeah
cutiecomittee123
  • cutiecomittee123
x^-1 is inverse
Nnesha
  • Nnesha
for that calculator press `2nd-sin` then type (5/8.6)
cutiecomittee123
  • cutiecomittee123
Ahh I see, way more acurate answer. x=35.55
Nnesha
  • Nnesha
got it !
Nnesha
  • Nnesha
that's right !
cutiecomittee123
  • cutiecomittee123
okay and then we have to find the csc of y, an you help
cutiecomittee123
  • cutiecomittee123
can*
Nnesha
  • Nnesha
i'll use the fact that all triangles add up to 180 degree so it's right triangle so one angle 90 other angle we just found 35.5 i don't knw why sin (x)= 8.6/7 gives me error on calculator
cutiecomittee123
  • cutiecomittee123
y=54.5
Nnesha
  • Nnesha
yes right
cutiecomittee123
  • cutiecomittee123
alright, i dont know if you still want to help but there are two more and i think i have the hang of it, but it is always nice to have a little help:) find tan c and cot y and find cos x and sec y
Nnesha
  • Nnesha
geez i don't know why it csc y giving me an error anyways \[\huge\rm csc( x )=\frac{ 8.6 }{ 7 }\] then find inverse csc
cutiecomittee123
  • cutiecomittee123
there is no csc button
Nnesha
  • Nnesha
with same triangle ?
Nnesha
  • Nnesha
i know but csc = 1/sin so it should be i /sin^{-1}(7/8.6)
cutiecomittee123
  • cutiecomittee123
yes same triangle Okay let me try that
cutiecomittee123
  • cutiecomittee123
so plug in 1/sin(-1) (7/8.6) ????
Nnesha
  • Nnesha
welll i plugged in sin^{-1} (7/8.6) i got 54.48
Nnesha
  • Nnesha
still don't understand anyways move to the next one
cutiecomittee123
  • cutiecomittee123
waiiiiittt, are we still working on the first problem to find csc(y)? because i got the same answer y=54.5 because i just used your advice that there are 180 degrees in a triangle and we already have 90+35.5 and then i subtracted them from 180 and got 54.5 as well. I think that is the right answer
Nnesha
  • Nnesha
yes that's the right answer but i was trying to find how to find csc y without using the fact 180 degree :D
Nnesha
  • Nnesha
\(\color{blue}{\text{Originally Posted by}}\) @cutiecomittee123 alright, i dont know if you still want to help but there are two more and i think i have the hang of it, but it is always nice to have a little help:) find `tan c` and cot y and find cos x and sec y \(\color{blue}{\text{End of Quote}}\) do you mean `tan x` ???
cutiecomittee123
  • cutiecomittee123
yes tan x
Nnesha
  • Nnesha
alright try it first remember cot is reciprocal of tan
cutiecomittee123
  • cutiecomittee123
well tan(x)=5/7
Nnesha
  • Nnesha
right solve for x !
cutiecomittee123
  • cutiecomittee123
Okay so I would just multiply by 7 on each side and that makes it 7tan(x)=35
Nnesha
  • Nnesha
well you don't have to multiply by 7 just take the invs tan and then calculator
cutiecomittee123
  • cutiecomittee123
okay so i did 2nd, tan(5/7) and i got 35.54
Nnesha
  • Nnesha
perfect!
cutiecomittee123
  • cutiecomittee123
i did it? is that it lol
Nnesha
  • Nnesha
yes right that's tan x
cutiecomittee123
  • cutiecomittee123
okay so now to find cot y
cutiecomittee123
  • cutiecomittee123
wouldnt it just be cot y = 7/5
cutiecomittee123
  • cutiecomittee123
oh is it just tan(5/7)
Nnesha
  • Nnesha
tan y = what ?
cutiecomittee123
  • cutiecomittee123
well it is inverse tan so i figured you use tan when calculating
Nnesha
  • Nnesha
well you did the opposite tan = opposite over adjacent and cot = adjacent over opposite
cutiecomittee123
  • cutiecomittee123
so you keep it the way it is but just dont take the iverse? sine we took the inverse to find tan x
cutiecomittee123
  • cutiecomittee123
inverse since *
Nnesha
  • Nnesha
guess what i'm so hungry right now i need 2nd opinion on this one i feel like we don't need angle we just write in the form tan x = 7/5 that's it
Nnesha
  • Nnesha
is it just find sin x or solve for x ?
Nnesha
  • Nnesha
or like what is x and y ?
Nnesha
  • Nnesha
\(\color{blue}{\text{Originally Posted by}}\) @cutiecomittee123 wouldnt it just be cot y = 7/5 \(\color{blue}{\text{End of Quote}}\) cot y = 5/7 ( adjacent over opposite) so it would be arctan(7/5)
Nnesha
  • Nnesha
ye then cos = adjacent over hyp so same concept with sec just like cot i think ur afk
Nnesha
  • Nnesha
i've to go now.
cutiecomittee123
  • cutiecomittee123
okay i see. Thanks for your help!!!
Nnesha
  • Nnesha
yw

Looking for something else?

Not the answer you are looking for? Search for more explanations.