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anonymous

  • one year ago

In his famous race, a hare runs for a while, takes a nap, and then resumes running until he reaches the finish line. His total displacement from start to finish is 5.0 m east and 12 m north. The hare's total race time, including the time of napping, is 28 minutes. What is the hare's average speed in meters per minute? someone please help :c

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  1. IrishBoy123
    • one year ago
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    use Pythagoraes to combine the distances... use the net displacement to get average speed

  2. anonymous
    • one year ago
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    so 5^2 + 12^2?

  3. IrishBoy123
    • one year ago
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    yes \[\sqrt{5^2 + 12^2}\]

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