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a1234

  • one year ago

Find the point (x, y) on the unit circle that corresponds to the real number 5pi/6. Use it to evaluate cos t. cos t = (-sqrt(3)/2)?

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  1. Michele_Laino
    • one year ago
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    by definition, we can write: \[\Large \begin{gathered} x = \cos \left( {\frac{{5\pi }}{6}} \right) = ...? \hfill \\ \hfill \\ y = \sin \left( {\frac{{5\pi }}{6}} \right) = \sqrt {1 - {{\left\{ {\cos \left( {\frac{{5\pi }}{6}} \right)} \right\}}^2}} = ...? \hfill \\ \end{gathered} \]

  2. Michele_Laino
    • one year ago
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    for the y-coordinate I choose the positive square rooth since your point is at II quadrant

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