anonymous
  • anonymous
Does anyone know how to do the opposite of distribution? I give medal.
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
x-3xy = 1. I have to solve for y
Nnesha
  • Nnesha
well for `opposite of distribution` you have to take out the common factor like aB+aC= a(b+c)
anonymous
  • anonymous
but do I have to for this problem do a fraction because their is no Y for the x in the front of the problem. It has to be something like y(___ +3x) = 1

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

Nnesha
  • Nnesha
well what is common in these two terms x-3xy ??
Nnesha
  • Nnesha
btw there is one with x 1x-3xy
anonymous
  • anonymous
the x is common so should I try to turn that into a distributive problem first? I would get x(1+3y)= 1
Nnesha
  • Nnesha
yes right but 3y is negative so \[\huge\rm x(1-3y)=1\] now move the x to the right side
anonymous
  • anonymous
1-3y=1/x
Nnesha
  • Nnesha
perfect
Nnesha
  • Nnesha
what would be the next step ?
anonymous
  • anonymous
-3y=1/x -1
anonymous
  • anonymous
|dw:1441832388127:dw|
Nnesha
  • Nnesha
yes right so both terms are dividing by -3 so you can write it as |dw:1441832500945:dw|
Nnesha
  • Nnesha
so \[\frac{ \frac{ 1 }{ x } }{ -3 } = ?\]
anonymous
  • anonymous
0_0
Nnesha
  • Nnesha
o^_^o multiply the top with the `reciprocal` of the bottom
anonymous
  • anonymous
|dw:1441832579715:dw|
Nnesha
  • Nnesha
|dw:1441832658208:dw| 1/x not 5 yes right now multiply the top fraction with the reciprocal of the bottom fraction
anonymous
  • anonymous
|dw:1441832707298:dw|
anonymous
  • anonymous
I might have forgotten how to multiply fractions. it is from left to right, right? not cross multiplication
Nnesha
  • Nnesha
5 how did u get 5 ?
Nnesha
  • Nnesha
what is the reciprocal of `-3/1` > ?
anonymous
  • anonymous
Oh I'm sorry I didn't put the second part of the question. x-3xy = 1. Solve for y. then find y if x = -5.
anonymous
  • anonymous
the reciprocal of -3/1 is 1/-3
Nnesha
  • Nnesha
alright first we should solve for y then we can replace by -5 and yes reciprocal|dw:1441833141499:dw| is 1/-3
Nnesha
  • Nnesha
\[\huge\rm y=\frac{ 1 -}{ x } \times \frac{ 1 }{ -3 }-\frac{ 1 }{ -3 }\] simplify this first then substitute x for -5
anonymous
  • anonymous
So, now I got the equation for y and I need to plug in X for what y =s
Nnesha
  • Nnesha
yes right substitute x for -5
anonymous
  • anonymous
|dw:1441833342964:dw|
Nnesha
  • Nnesha
\[\huge\rm y=\frac{ 1 -}{ x } \times \frac{ 1 }{ -3 }-\frac{ 1 }{ -3 }\] first simplify this
anonymous
  • anonymous
|dw:1441833454633:dw|
Nnesha
  • Nnesha
hmm no
Nnesha
  • Nnesha
\[\huge\rm y=\color{ReD}{\frac{ 1 -}{ x } \times \frac{ 1 }{ -3 }}-\frac{ 1 }{ -3 }\] simplify the red part first don't replace x for -5 yet
anonymous
  • anonymous
i do this by cross multiplication? or does the answer of the numerator have to be the same as the denominator?
Nnesha
  • Nnesha
just multiply the numerator by numerator and the denominator by denominator
Nnesha
  • Nnesha
no not cross multiplication
anonymous
  • anonymous
ok|dw:1441833634950:dw|
anonymous
  • anonymous
|dw:1441833735641:dw|
Nnesha
  • Nnesha
yes right so negative divide by negative equal positive so -1/-3 \[\huge\rm y = -\frac{ 1 }{ 3x }+\frac{ 1 }{3 }\] and there is typo it should be 1/-3x sorry about that
anonymous
  • anonymous
|dw:1441833868729:dw|
anonymous
  • anonymous
so y = 4/15?
Nnesha
  • Nnesha
no
anonymous
  • anonymous
what part was wrong in my solving?
Nnesha
  • Nnesha
|dw:1441834075300:dw|
Nnesha
  • Nnesha
|dw:1441834145872:dw| negative divide by negative = positive
anonymous
  • anonymous
I got -1/15
Nnesha
  • Nnesha
that was your mistake ^^^^ negative divide by negative = posistive
Nnesha
  • Nnesha
|dw:1441834239060:dw| negative should cancels out
anonymous
  • anonymous
what positive number is the -1 being multiplied by?
anonymous
  • anonymous
-1*
anonymous
  • anonymous
negative* ^^
Nnesha
  • Nnesha
|dw:1441834316056:dw| 3 times -5 = -15 so both negatives ( numerator and the denominator one would cancel each other out) that was your mistake other works is right so now add instead subtraction
anonymous
  • anonymous
ok that's what i didn't understand how they numerator and the denominator both get their sign changed
Nnesha
  • Nnesha
\(\color{blue}{\text{Originally Posted by}}\) @Nnesha yes right so negative divide by negative equal positive so -1/-3 \[\huge\rm y = -\frac{ 1 }{ 3x }+\frac{ 1 }{3 }\] and there is typo it should be 1/-3x sorry about that \(\color{blue}{\text{End of Quote}}\) this is what we got after solving for y agree ?
anonymous
  • anonymous
|dw:1441834466580:dw|
Nnesha
  • Nnesha
lO_Oks good! great job!
anonymous
  • anonymous
Thank you so much I have a big Alg 2 test tomorrow. And what i learned from you about fractions saved my life. :D Sorry it took so long.
Nnesha
  • Nnesha
it was fun working with you great student! i wish you all the best for the test good luck!!!! focus on signs !!!
anonymous
  • anonymous
thank you. good bye
Nnesha
  • Nnesha
good bye

Looking for something else?

Not the answer you are looking for? Search for more explanations.