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anonymous

  • one year ago

Does anyone know how to do the opposite of distribution? I give medal.

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  1. anonymous
    • one year ago
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    x-3xy = 1. I have to solve for y

  2. Nnesha
    • one year ago
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    well for `opposite of distribution` you have to take out the common factor like aB+aC= a(b+c)

  3. anonymous
    • one year ago
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    but do I have to for this problem do a fraction because their is no Y for the x in the front of the problem. It has to be something like y(___ +3x) = 1

  4. Nnesha
    • one year ago
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    well what is common in these two terms x-3xy ??

  5. Nnesha
    • one year ago
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    btw there is one with x 1x-3xy

  6. anonymous
    • one year ago
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    the x is common so should I try to turn that into a distributive problem first? I would get x(1+3y)= 1

  7. Nnesha
    • one year ago
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    yes right but 3y is negative so \[\huge\rm x(1-3y)=1\] now move the x to the right side

  8. anonymous
    • one year ago
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    1-3y=1/x

  9. Nnesha
    • one year ago
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    perfect

  10. Nnesha
    • one year ago
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    what would be the next step ?

  11. anonymous
    • one year ago
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    -3y=1/x -1

  12. anonymous
    • one year ago
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    |dw:1441832388127:dw|

  13. Nnesha
    • one year ago
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    yes right so both terms are dividing by -3 so you can write it as |dw:1441832500945:dw|

  14. Nnesha
    • one year ago
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    so \[\frac{ \frac{ 1 }{ x } }{ -3 } = ?\]

  15. anonymous
    • one year ago
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    0_0

  16. Nnesha
    • one year ago
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    o^_^o multiply the top with the `reciprocal` of the bottom

  17. anonymous
    • one year ago
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    |dw:1441832579715:dw|

  18. Nnesha
    • one year ago
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    |dw:1441832658208:dw| 1/x not 5 yes right now multiply the top fraction with the reciprocal of the bottom fraction

  19. anonymous
    • one year ago
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    |dw:1441832707298:dw|

  20. anonymous
    • one year ago
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    I might have forgotten how to multiply fractions. it is from left to right, right? not cross multiplication

  21. Nnesha
    • one year ago
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    5 how did u get 5 ?

  22. Nnesha
    • one year ago
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    what is the reciprocal of `-3/1` > ?

  23. anonymous
    • one year ago
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    Oh I'm sorry I didn't put the second part of the question. x-3xy = 1. Solve for y. then find y if x = -5.

  24. anonymous
    • one year ago
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    the reciprocal of -3/1 is 1/-3

  25. Nnesha
    • one year ago
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    alright first we should solve for y then we can replace by -5 and yes reciprocal|dw:1441833141499:dw| is 1/-3

  26. Nnesha
    • one year ago
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    \[\huge\rm y=\frac{ 1 -}{ x } \times \frac{ 1 }{ -3 }-\frac{ 1 }{ -3 }\] simplify this first then substitute x for -5

  27. anonymous
    • one year ago
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    So, now I got the equation for y and I need to plug in X for what y =s

  28. Nnesha
    • one year ago
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    yes right substitute x for -5

  29. anonymous
    • one year ago
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    |dw:1441833342964:dw|

  30. Nnesha
    • one year ago
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    \[\huge\rm y=\frac{ 1 -}{ x } \times \frac{ 1 }{ -3 }-\frac{ 1 }{ -3 }\] first simplify this

  31. anonymous
    • one year ago
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    |dw:1441833454633:dw|

  32. Nnesha
    • one year ago
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    hmm no

  33. Nnesha
    • one year ago
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    \[\huge\rm y=\color{ReD}{\frac{ 1 -}{ x } \times \frac{ 1 }{ -3 }}-\frac{ 1 }{ -3 }\] simplify the red part first don't replace x for -5 yet

  34. anonymous
    • one year ago
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    i do this by cross multiplication? or does the answer of the numerator have to be the same as the denominator?

  35. Nnesha
    • one year ago
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    just multiply the numerator by numerator and the denominator by denominator

  36. Nnesha
    • one year ago
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    no not cross multiplication

  37. anonymous
    • one year ago
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    ok|dw:1441833634950:dw|

  38. anonymous
    • one year ago
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    |dw:1441833735641:dw|

  39. Nnesha
    • one year ago
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    yes right so negative divide by negative equal positive so -1/-3 \[\huge\rm y = -\frac{ 1 }{ 3x }+\frac{ 1 }{3 }\] and there is typo it should be 1/-3x sorry about that

  40. anonymous
    • one year ago
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    |dw:1441833868729:dw|

  41. anonymous
    • one year ago
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    so y = 4/15?

  42. Nnesha
    • one year ago
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    no

  43. anonymous
    • one year ago
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    what part was wrong in my solving?

  44. Nnesha
    • one year ago
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    |dw:1441834075300:dw|

  45. Nnesha
    • one year ago
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    |dw:1441834145872:dw| negative divide by negative = positive

  46. anonymous
    • one year ago
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    I got -1/15

  47. Nnesha
    • one year ago
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    that was your mistake ^^^^ negative divide by negative = posistive

  48. Nnesha
    • one year ago
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    |dw:1441834239060:dw| negative should cancels out

  49. anonymous
    • one year ago
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    what positive number is the -1 being multiplied by?

  50. anonymous
    • one year ago
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    -1*

  51. anonymous
    • one year ago
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    negative* ^^

  52. Nnesha
    • one year ago
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    |dw:1441834316056:dw| 3 times -5 = -15 so both negatives ( numerator and the denominator one would cancel each other out) that was your mistake other works is right so now add instead subtraction

  53. anonymous
    • one year ago
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    ok that's what i didn't understand how they numerator and the denominator both get their sign changed

  54. Nnesha
    • one year ago
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    \(\color{blue}{\text{Originally Posted by}}\) @Nnesha yes right so negative divide by negative equal positive so -1/-3 \[\huge\rm y = -\frac{ 1 }{ 3x }+\frac{ 1 }{3 }\] and there is typo it should be 1/-3x sorry about that \(\color{blue}{\text{End of Quote}}\) this is what we got after solving for y agree ?

  55. anonymous
    • one year ago
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    |dw:1441834466580:dw|

  56. Nnesha
    • one year ago
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    lO_Oks good! great job!

  57. anonymous
    • one year ago
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    Thank you so much I have a big Alg 2 test tomorrow. And what i learned from you about fractions saved my life. :D Sorry it took so long.

  58. Nnesha
    • one year ago
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    it was fun working with you great student! i wish you all the best for the test good luck!!!! focus on signs !!!

  59. anonymous
    • one year ago
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    thank you. good bye

  60. Nnesha
    • one year ago
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    good bye

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