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anonymous
 one year ago
Find x in this proportion.
x3 = x+25
(they are fractions. Please show answer and how you got it!)
anonymous
 one year ago
Find x in this proportion. x3 = x+25 (they are fractions. Please show answer and how you got it!)

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Nnesha @e.mccormick @Donblue

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2So x is to 3 as x+2 is to 5? Know how to set those up in fractional form?

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.0\(\frac{x}{3}=x+\frac{2}{5}\) I think the easiest thing would be to multiply everything by the LCM of the denominators, which is 15 \(15\frac{x}{3}=15x+15\frac{2}{5}\) \(5x=15x+6\) Can you solve now?

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2zz, I think they meant: \(\dfrac{x}{3} = \dfrac{x+2}{5}\)

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.0Was it \(\frac{x}{3}=\frac{x+2}{5}\)?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0x/3=x+ 2/5 or , 5x=15x+6 or, 15x+6=5x or,10x=6 or,x=6/10=3/5=0.6

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ye @e.mccormick and @Learner11 i tried that, thats wrong

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.0ahh, try the same thing with that! \[\frac{x}{3}=\frac{x+2}{5}\] \[15*\frac{x}{3}=15*\frac{x+2}{5}\] \[5x=3(x+2)\] now solve for \(x\)?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0answer choices are 1 , 1 , 2, 3. :P i keep doin this wrong

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2As a general rule: \(\dfrac{a}{b}=\dfrac{c}{d}\) type proportions can alsways use cross multiplication to move forward. Cross multiplication basically does what xx did. He just multiplied hte bottoms (3 and 5) first. But if you don't multiply them out, then you can cancel quickly: \(\dfrac{a}{b}=\dfrac{c}{d}\) \(\dfrac{a}{b}\times \dfrac{bd}{1}=\dfrac{c}{d}\times \dfrac{bd}{1}\) \(\dfrac{a}{\cancel{b}}\times \dfrac{\cancel{b}d}{1}=\dfrac{c}{\cancel{d}}\times \dfrac{b\cancel{d}}{1}\) \(\dfrac{a}{1}\times \dfrac{d}{1}=\dfrac{c}{1}\times \dfrac{b}{1}\) \(a\times d=c\times b\) \(ad=cb\) That is a general way to start. Then solve for the unknown...

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2What steps are you using when you solve the: 5x=3(x+2)
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