anonymous
  • anonymous
Find x in this proportion. x|3 = x+2|5 (they are fractions. Please show answer and how you got it!)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
@Nnesha @e.mccormick @Donblue
e.mccormick
  • e.mccormick
So x is to 3 as x+2 is to 5? Know how to set those up in fractional form?
zzr0ck3r
  • zzr0ck3r
\(\frac{x}{3}=x+\frac{2}{5}\) I think the easiest thing would be to multiply everything by the LCM of the denominators, which is 15 \(15\frac{x}{3}=15x+15\frac{2}{5}\) \(5x=15x+6\) Can you solve now?

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e.mccormick
  • e.mccormick
zz, I think they meant: \(\dfrac{x}{3} = \dfrac{x+2}{5}\)
zzr0ck3r
  • zzr0ck3r
Was it \(\frac{x}{3}=\frac{x+2}{5}\)?
anonymous
  • anonymous
x/3=x+ 2/5 or , 5x=15x+6 or, 15x+6=5x or,10x=6 or,x=6/10=3/5=0.6
anonymous
  • anonymous
ye @e.mccormick and @Learner11 i tried that, thats wrong
zzr0ck3r
  • zzr0ck3r
ahh, try the same thing with that! \[\frac{x}{3}=\frac{x+2}{5}\] \[15*\frac{x}{3}=15*\frac{x+2}{5}\] \[5x=3(x+2)\] now solve for \(x\)?
anonymous
  • anonymous
answer choices are -1 , 1 , 2, 3. :P i keep doin this wrong
e.mccormick
  • e.mccormick
As a general rule: \(\dfrac{a}{b}=\dfrac{c}{d}\) type proportions can alsways use cross multiplication to move forward. Cross multiplication basically does what xx did. He just multiplied hte bottoms (3 and 5) first. But if you don't multiply them out, then you can cancel quickly: \(\dfrac{a}{b}=\dfrac{c}{d}\) \(\dfrac{a}{b}\times \dfrac{bd}{1}=\dfrac{c}{d}\times \dfrac{bd}{1}\) \(\dfrac{a}{\cancel{b}}\times \dfrac{\cancel{b}d}{1}=\dfrac{c}{\cancel{d}}\times \dfrac{b\cancel{d}}{1}\) \(\dfrac{a}{1}\times \dfrac{d}{1}=\dfrac{c}{1}\times \dfrac{b}{1}\) \(a\times d=c\times b\) \(ad=cb\) That is a general way to start. Then solve for the unknown...
anonymous
  • anonymous
thank you!
e.mccormick
  • e.mccormick
What steps are you using when you solve the: 5x=3(x+2)

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