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anonymous

  • one year ago

A drill began digging a well 48 3/5 feet above sea level.When the work was complete,the drill had dug in to the ground to a depth of 12 1/2 feet below sea level.How far did the drill dig in all?

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  1. anonymous
    • one year ago
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    so final height - initial height = distance. Think sea level as 0, so -12 1/2 - 48 3/5 = ?

  2. anonymous
    • one year ago
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    and then take the absolute value of the answer, because distance can't be negative.

  3. anonymous
    • one year ago
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    Wait...wouldn't it be 48 3/5 - -12 1/2?

  4. anonymous
    • one year ago
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    same either way.

  5. anonymous
    • one year ago
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    I still don't get it

  6. anonymous
    • one year ago
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    Why subtract?

  7. anonymous
    • one year ago
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    It's the total distance

  8. anonymous
    • one year ago
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    \[\left(48+\frac{3}{5}\right)-\left(-12-\frac{1}{2}\right)=\frac{174}{5}=34+\frac{4}{5} \]

  9. anonymous
    • one year ago
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    vicky191, think about it this way. if a plane starts 2m above ground and stops at 4m above ground, Wouldn't you do 4-2 to find the distance? ( you could also do 2-4 and take the absolute value. Either way the answer will be 2m.) Similarly, you could do -12 1/2 - 48 3/5 as well as 48 3/5 - (-12 1/2).

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