A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

Trisaba

  • one year ago

P(x> or = x line over + 2 standard deviation) medal and fan

  • This Question is Closed
  1. Trisaba
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i got one more two similar

  2. Trisaba
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    normal distributions

  3. Trisaba
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    x line over means there is a line over the x

  4. Trisaba
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @superman36

  5. Trisaba
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @Jaynator495

  6. Trisaba
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    someone

  7. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[P(x\ge \bar{x}+2\sigma)~~?\] How is \(x\) distributed? If you're given a normal distribution, this is straightforward if you know the empirical rule: https://en.wikipedia.org/wiki/68%E2%80%9395%E2%80%9399.7_rule

  8. Trisaba
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    it has no labels they want like 68% is 34% + 34%

  9. Trisaba
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @SithsAndGiggles

  10. Trisaba
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    we have to use the normal ditribution example ones from this line to this

  11. Trisaba
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

  12. Trisaba
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    3 and 4

  13. Trisaba
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    4 and 5 sorry wrong numbers

  14. Trisaba
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    what am i supposed to do

  15. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1441842345311:dw| From the rule, you have that \[\begin{cases} D+E=68\\ C+D+E+F=95\\ B+C+D+E+F+G=99.7\\ A+B+C+D+E+F+G+H=1 \end{cases}\] The distribution is symmetric, so you can determine that \[\begin{cases} D=E=34\\ C=F=13.5\\ B=G=2.35\\ A=H=0.15 \end{cases}\]

  16. Trisaba
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    where is x

  17. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    So for your first problem, \[P(x\ge \bar{x}+2\sigma)=G+H=\cdots\]

  18. Trisaba
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    x with the line over it is the mean

  19. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I have \(\bar{x}\) labeled on the graph above in the middle of the curve.

  20. Trisaba
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i know

  21. Trisaba
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    im confused

  22. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    All I've done is rephrase the problem from \(P(x\ge\bar{x}+2\sigma)\) to the simple operation \(2.35+0.15\). The areas of the regions are probabilities.

  23. Trisaba
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    how did you do that

  24. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    The area of the shaded region is the probability you're looking for: |dw:1441843152498:dw| Are you wondering how I found \(G=2.35\) and \(H=0.15\)?

  25. Trisaba
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i thought h is 1.15

  26. Trisaba
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    nevermind

  27. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Well, we have \[B+C+D+E+F+G=99.7\] so substituting this into the total probability equation (the last equation in the system above), we get \[\begin{align*}1&=A+B+C+D+E+F+G+H\\ 1&=A+99.7+H\\ 0.3&=A+H\\ 0.3&=A+A\\ 0.3&=2A\\ 0.15&=A=H \end{align*}\]

  28. Trisaba
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    what is x though

  29. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \(x\) is completely symbolic here. It's referring to some event or characteristic that occurs with probability modeled by the curve. It can take on any value in the domain of the distribution. Let's say we're talking about the heights of a large group of people. \(\bar{x}\) is the average of height, while \(x\) can be any height that is seen among the group of people. So as an example, the statement \(P(x=5)\) is the same as "the probability that any given person's height is \(5\) (units)". Meanwhile, \(P(x>5)\) means "the probability that any given person's height is greater than \(5\)", and so on. Does that make sense?

  30. Trisaba
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes

  31. Trisaba
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so the answer is a group of probabilities?

  32. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    The answers are the sums of the areas that belong in the desired intervals. I've already shaded the one you're interested in for (4). (5) is just as easy: |dw:1441844287564:dw| or \(A+B+C+D+E\).

  33. Trisaba
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    and 4?

  34. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[P(x\ge \bar{x}+2\sigma)=G+H\]

  35. Trisaba
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    2.5?

  36. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Yes

  37. Trisaba
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    thank you so much

  38. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yw

  39. Trisaba
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    bye

  40. Trisaba
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    wait actually i forgot 6 too

  41. Trisaba
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    please @SithsAndGiggles

  42. Trisaba
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    nevermind

  43. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.