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anonymous
 one year ago
Give the corners of the feasible set:
D=7x+20y
subject to 2x +y less than equal to8
4x +6y less than equal 24
x greater than or equal to 0
y greater to or equal to 0
I already have my 6 points ... I need help figuring out if its a maximum or minimum
anonymous
 one year ago
Give the corners of the feasible set: D=7x+20y subject to 2x +y less than equal to8 4x +6y less than equal 24 x greater than or equal to 0 y greater to or equal to 0 I already have my 6 points ... I need help figuring out if its a maximum or minimum

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[2x+y \le8 ...(1)\] \[4x+6y \le 24 \] \[or~2x+3y \le 12~~~...(2)\] consider 2x+y=8 x=0,y=8 y=0,x=4 so points are (0,8) and (4,0) again consider 2x+3y=12 x=0,y=4 y=0,x=6 so points are (0,4) and (6,0) \[x \ge0,y \ge0 \] graph lies in the first quadrant. put x=0,y=0 in (1) \[0+0\le 8 \] (0,0) lies in the graph of first line . similarly (0,0) lies in the graph of second line' 2x+y=8 2x+3y=12 subtract 2y=4,y=2 2x+2=8 2x=82=6 x=3 point of intersection is (3dw:1441850946561:dw,2) draw the graph

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh great! that is exactly what I got. So if 8≤0+0 would I shade above my intersection? Also I got 80 for my max and 0 for my min.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(0,8) and (6,0) are not in the feasible region

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0if\[2x+y \ge 8,0+0\ge8\] which is not true so (0,0) does not le on the graph so we had to shade right of this line

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0then only three points (4,0),(6,0) and (3,2)
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