Calculate the number of moles of helium that contains 3.25 x 10^21 atoms.

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Calculate the number of moles of helium that contains 3.25 x 10^21 atoms.

Chemistry
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Without numbers, can you figure this out. Always start with given value \[\frac{ atoms}{ 1}\times \frac{ mol }{ atoms }\]
3.25 x 10^ 21 atom x (1mol/6.022 x 10 23 atom)
Right?

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\[3.25 x 10^{21} atom x \frac{ 1 mol }{ 6.022 x 10^{23} atom }\]
Yes, that is right. Sorry I was helping someone.
And I get .539687811
Units would be in moles of helium.
So .539687811 mol He?
It has to be 3 sf since the given value only has 3. Remember that your answer has a 0 in the front. It does not count as a sf.
.540 mol He?
Yes Nice rounding!
Thanks
No problem!
It's saying the answer is wrong. I did it right...Right?
I did not do the calculations since you got the right conversion. You did the calculation. Do the calculation again.
I think you put 3.25*10^23 instead of 3.25*10^21
I did it again and got the same answer.
Write down what you calculate then.
\[3.25\times10^{21} atomtimes \frac{ 1mol }{ 6.022 \times10^{23 } }atom\]
3.25 x 10^21 atom x
Dont forget parentheses. (3.25*10^21)/(6.022*10^23)
Right
Got .00540 mol He
So what did you do wrong earlier?
Forgot parentheses or wrong exponent?
I put it in the calculator without parentheses
Another way is multiply 3.25*10^21 and lets called that x then multiply 6.023*10^23 and call that y. Then just do x/y if you arent comfortable with parentheses.

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