anonymous
  • anonymous
Super Confused...Any help is appreciated. Its Geometry btw
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
wat im posting it
anonymous
  • anonymous
i only need help with last 2 pages. The others are for references

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anonymous
  • anonymous
@jim_thompson5910 please help
anonymous
  • anonymous
@jim_thompson5910
anonymous
  • anonymous
@jim_thompson5910
anonymous
  • anonymous
@jim_thompson5910 please help
anonymous
  • anonymous
@ganeshie8
anonymous
  • anonymous
what do you need, the sine and cosine questions?
anonymous
  • anonymous
i just dont understand what im supposed to do on the last 2 pages.
anonymous
  • anonymous
what you need is a good trig cheat sheet look at the unit circle on the last page of the attached
anonymous
  • anonymous
lets say you want \[\cos(\frac{\pi}{6})\] find the angle \(\frac{\pi}{6}\) and look at the corresponding point on the unit circle the first coordinate of that point is \(\cos(\frac{\pi}{6})\) and the second coordinate is \(\sin(\frac{\pi}{6})\)
anonymous
  • anonymous
hmmm
anonymous
  • anonymous
let me know when you see it, then we can do one more
anonymous
  • anonymous
i see it, whats confusing me is that, im not sure what my teacher is wanting me to put in the blanks on the last 2 pages.
anonymous
  • anonymous
i think the values of sine and cosine asked for
anonymous
  • anonymous
as for the first question, since the radius is 1, instead of \[\cos(\theta)=\frac{opposite}{adjacent}\] it is just \[\cos(\theta)\] is the first coordinate of the point on the unit circle (since the hypotenuse is 1)
anonymous
  • anonymous
i still dont understand. sorry
anonymous
  • anonymous
|dw:1441853953843:dw|
jim_thompson5910
  • jim_thompson5910
yes that's the point on the unit circle when the angle is 30 degrees the x coordinate is equal to cos(30 degrees) the y coordinate is equal to sin(30 degrees) |dw:1441854248061:dw|
anonymous
  • anonymous
Is this the answer?
jim_thompson5910
  • jim_thompson5910
So that means \[\Large \cos(30^{\circ}) = \frac{\sqrt{3}}{2}\] \[\Large \sin(30^{\circ}) = \frac{1}{2}\]
anonymous
  • anonymous
|dw:1441854362314:dw|
anonymous
  • anonymous
so i would put |dw:1441854545172:dw|
jim_thompson5910
  • jim_thompson5910
30 degrees is NOT in quadrant 2
anonymous
  • anonymous
would this be right for quadrant 1??
jim_thompson5910
  • jim_thompson5910
yeah 30 degrees is in quadrant 1
anonymous
  • anonymous
change the 30 degrees to 120??
jim_thompson5910
  • jim_thompson5910
why do that?
anonymous
  • anonymous
because 120 degrees is in quadrant II
jim_thompson5910
  • jim_thompson5910
what would cos(120) be equal to
anonymous
  • anonymous
-1/2?
jim_thompson5910
  • jim_thompson5910
yes
jim_thompson5910
  • jim_thompson5910
and sin(120) ?
anonymous
  • anonymous
square root of 3 /2
jim_thompson5910
  • jim_thompson5910
good
anonymous
  • anonymous
Do i just do that for the rest of them???
jim_thompson5910
  • jim_thompson5910
yes
anonymous
  • anonymous
OK thanks a ton!
jim_thompson5910
  • jim_thompson5910
no problem

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