## anonymous one year ago Super Confused...Any help is appreciated. Its Geometry btw

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1. anonymous

wat im posting it

2. anonymous

3. anonymous

i only need help with last 2 pages. The others are for references

4. anonymous

5. anonymous

@jim_thompson5910

6. anonymous

@jim_thompson5910

7. anonymous

8. anonymous

@ganeshie8

9. anonymous

what do you need, the sine and cosine questions?

10. anonymous

i just dont understand what im supposed to do on the last 2 pages.

11. anonymous

what you need is a good trig cheat sheet look at the unit circle on the last page of the attached

12. anonymous

lets say you want $\cos(\frac{\pi}{6})$ find the angle $$\frac{\pi}{6}$$ and look at the corresponding point on the unit circle the first coordinate of that point is $$\cos(\frac{\pi}{6})$$ and the second coordinate is $$\sin(\frac{\pi}{6})$$

13. anonymous

hmmm

14. anonymous

let me know when you see it, then we can do one more

15. anonymous

i see it, whats confusing me is that, im not sure what my teacher is wanting me to put in the blanks on the last 2 pages.

16. anonymous

i think the values of sine and cosine asked for

17. anonymous

as for the first question, since the radius is 1, instead of $\cos(\theta)=\frac{opposite}{adjacent}$ it is just $\cos(\theta)$ is the first coordinate of the point on the unit circle (since the hypotenuse is 1)

18. anonymous

i still dont understand. sorry

19. anonymous

|dw:1441853953843:dw|

20. jim_thompson5910

yes that's the point on the unit circle when the angle is 30 degrees the x coordinate is equal to cos(30 degrees) the y coordinate is equal to sin(30 degrees) |dw:1441854248061:dw|

21. anonymous

22. jim_thompson5910

So that means $\Large \cos(30^{\circ}) = \frac{\sqrt{3}}{2}$ $\Large \sin(30^{\circ}) = \frac{1}{2}$

23. anonymous

|dw:1441854362314:dw|

24. anonymous

so i would put |dw:1441854545172:dw|

25. jim_thompson5910

30 degrees is NOT in quadrant 2

26. anonymous

would this be right for quadrant 1??

27. jim_thompson5910

yeah 30 degrees is in quadrant 1

28. anonymous

change the 30 degrees to 120??

29. jim_thompson5910

why do that?

30. anonymous

because 120 degrees is in quadrant II

31. jim_thompson5910

what would cos(120) be equal to

32. anonymous

-1/2?

33. jim_thompson5910

yes

34. jim_thompson5910

and sin(120) ?

35. anonymous

square root of 3 /2

36. jim_thompson5910

good

37. anonymous

Do i just do that for the rest of them???

38. jim_thompson5910

yes

39. anonymous

OK thanks a ton!

40. jim_thompson5910

no problem