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anonymous
 one year ago
Super Confused...Any help is appreciated. Its Geometry btw
anonymous
 one year ago
Super Confused...Any help is appreciated. Its Geometry btw

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i only need help with last 2 pages. The others are for references

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@jim_thompson5910 please help

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@jim_thompson5910 please help

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what do you need, the sine and cosine questions?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i just dont understand what im supposed to do on the last 2 pages.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what you need is a good trig cheat sheet look at the unit circle on the last page of the attached

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0lets say you want \[\cos(\frac{\pi}{6})\] find the angle \(\frac{\pi}{6}\) and look at the corresponding point on the unit circle the first coordinate of that point is \(\cos(\frac{\pi}{6})\) and the second coordinate is \(\sin(\frac{\pi}{6})\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0let me know when you see it, then we can do one more

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i see it, whats confusing me is that, im not sure what my teacher is wanting me to put in the blanks on the last 2 pages.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i think the values of sine and cosine asked for

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0as for the first question, since the radius is 1, instead of \[\cos(\theta)=\frac{opposite}{adjacent}\] it is just \[\cos(\theta)\] is the first coordinate of the point on the unit circle (since the hypotenuse is 1)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i still dont understand. sorry

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441853953843:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1yes that's the point on the unit circle when the angle is 30 degrees the x coordinate is equal to cos(30 degrees) the y coordinate is equal to sin(30 degrees) dw:1441854248061:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1So that means \[\Large \cos(30^{\circ}) = \frac{\sqrt{3}}{2}\] \[\Large \sin(30^{\circ}) = \frac{1}{2}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441854362314:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so i would put dw:1441854545172:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.130 degrees is NOT in quadrant 2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0would this be right for quadrant 1??

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1yeah 30 degrees is in quadrant 1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0change the 30 degrees to 120??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0because 120 degrees is in quadrant II

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1what would cos(120) be equal to

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1and sin(120) ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Do i just do that for the rest of them???
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