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what grade u in ??
@*ImaBeMe* I find that irrelevant,if your not going to help please hit that log out option and annoy someone else.
hint: |dw:1441844647460:dw| solve for \(\Large \theta\)
I agree please leave if you arent willling to help I am trying to keep my schedule organized and I actually am in need of help. this is not a dating website.
another hint: |dw:1441844715344:dw|
ok i just asked dang
this is precalculus incase youre wondering.
if you aren't familiar with the trig ratios, this chart may help http://passyworldofmathematics.com/Images/pwmImagesSix/TrigRatiosSix550x389JPG.jpg
alright so sinfeta=50/x
then take the inverse right?
theta = \(\Large \theta\) it's a greek letter
which two sides are known to us? (pick between opposite, adjacent, hypotenuse)
we know opposite and adjacent. which are opposite=50 and adjacent=75
yep, which trig function uses opposite and adjacent?
but it is asking to find sine
oh I see, I was thinking they just wanted theta, nvm
ok so you'll need the hypotenuse first because sin(theta) = opp/hyp
Wait up i remember this in Geometry, are you sure it isnt Geometry
so use the pythagorean theorem to find x |dw:1441845085421:dw| a^2 + b^2 = c^2 50^2 + 75^2 = x^2 x = ???
you do learn this in geometry, if you want to try and give it a shot, i wont stop you lol
you have one more step to go
uhh that is where i need help
dont you just take the inverse
use a calculator to compute 50/90.14
okay i got .5546
I'm getting 50/90.14 = 0.55469270024407 which rounds to 0.5547
and that is what the angle sin is equal to right?
that decimal value is equal to \(\Large \sin(\theta)\), yes
okay cool, and that is it right?