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what grade u in ??

hint:
|dw:1441844647460:dw|
solve for \(\Large \theta\)

another hint:
|dw:1441844715344:dw|

ok i just asked dang

this is precalculus incase youre wondering.

alright so sinfeta=50/x

then take the inverse right?

theta = \(\Large \theta\)
it's a greek letter

Oh gotcha

which two sides are known to us? (pick between opposite, adjacent, hypotenuse)

we know opposite and adjacent. which are opposite=50 and adjacent=75

yep, which trig function uses opposite and adjacent?

but it is asking to find sine

oh I see, I was thinking they just wanted theta, nvm

ok so you'll need the hypotenuse first because sin(theta) = opp/hyp

Wait up i remember this in Geometry, are you sure it isnt Geometry

you do learn this in geometry, if you want to try and give it a shot, i wont stop you lol

c=90.14

sintheta=50/90.14

you have one more step to go

uhh that is where i need help

dont you just take the inverse

use a calculator to compute 50/90.14

okay i got .5546

I'm getting 50/90.14 = 0.55469270024407 which rounds to 0.5547

yes!

and that is what the angle sin is equal to right?

that decimal value is equal to \(\Large \sin(\theta)\), yes

okay cool, and that is it right?