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Goose.

  • one year ago

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  1. Goose.
    • one year ago
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    Given that f(x) = 3x + 1 and g(x) = the quantity of 4x plus 2 divided by 3, solve for g(f(0)). 2 6 8 9

  2. anonymous
    • one year ago
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    The best way to think about this problem is what are you plugging int to what? g(f(0)) means, you plug 0 into f(x). Whatever number you get from that, you plug into g(x)!

  3. Goose.
    • one year ago
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    I'm really confused, Please walk me through it...

  4. Goose.
    • one year ago
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    If I plug in 0 for f(x)...

  5. anonymous
    • one year ago
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    4(3x+1)+234(3x+1)+23 First let's find F(0). Plug in 0 for x in F(x) F(x) = 3x +1 F(0) = 3(0) + 1 F(0) = 0 +1 F(0) = 1

  6. Goose.
    • one year ago
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    Okay I wasn't sure what you meant by the plugging 0 into f(x) But I get it now,

  7. anonymous
    • one year ago
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    So now, you plug in 1 into g(x) G(1) = ????? G(x)= 4x+23 G(1)= 4(1)+23 G(1)= 63 G(1)= 21 = 2 G(1)=2

  8. Goose.
    • one year ago
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    Okay thanks! Now I will know how to do the rest!

  9. anonymous
    • one year ago
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    cx awesome

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