is3535
  • is3535
What value of p solves the equation?
Mathematics
jamiebookeater
  • jamiebookeater
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is3535
  • is3535
|dw:1441842713159:dw|
is3535
  • is3535
is3535
  • is3535

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is3535
  • is3535
5 * 5 * 5 * 5 * 5 = 25
is3535
  • is3535
p^-5 =1/243
is3535
  • is3535
is3535
  • is3535
is3535
  • is3535
is3535
  • is3535
is3535
  • is3535
phi
  • phi
first, flip \[ p^{-5} \] what do you get ?
is3535
  • is3535
5 * 5 * 5 * 5 * 5 = 25
phi
  • phi
no. just change \[ \frac{p^{-5}}{1} = \frac{1}{p^5} \] notice you flip it upside down and change -5 to +5
phi
  • phi
your problem is now \[ \frac{1}{p^5}= \frac{1}{243} \] you can flip both sides, \[ p^5 = 243\]
is3535
  • is3535
so that my answer
phi
  • phi
you know p*p*p*p*p is 243 to find p we could try factoring 243 or we can try guessing p for example if p=1 we get 1*1*1*1*1= 1 which is too small also if p=2 we would get 2*2*2*2*2= 32 still too small what about p=3?
is3535
  • is3535
3 * 3*3*3*3= 243
phi
  • phi
that works. so p is 3
is3535
  • is3535
so 3 is my answer
phi
  • phi
yes
is3535
  • is3535
omg ty

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