Goose.
  • Goose.
Seriously confused! Will medal!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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Goose.
  • Goose.
Given f(x) = the quantity of 4x plus 1, divided by 3, solve for f−1(3). 2 4 6 8
Goose.
  • Goose.
I know that something to the ^-1 power is basically the recipricol.. like 5^-1 would be 1/5 but how would I do the fraction in this problem?
anonymous
  • anonymous
f^-1(x) is not the same as 1/f(x) The easiest method to solve this is to write y instead of f(x). Then you solve the equation for x in terms of y. f(x) = (4x+1)/3 y=(4x+1)/3 3y=4x+1 . . . x=(3y-1)/4 f^-1(x)=(3x-1)/4 f^-1(3)=2

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jim_thompson5910
  • jim_thompson5910
Equivalently, you can plug in y = 3 and solve for x to get the same answer y=(4x+1)/3 3=(4x+1)/3 ... ... ... x = 2
jim_thompson5910
  • jim_thompson5910
The notation \(\Large f^{-1}(x)\) means "f inverse" or "the inverse of f(x)" like jualbafer wrote, it is NOT the same as \(\LARGE \frac{1}{f(x)}\) yes it's confusing because the negative one exponent has 2 different meanings

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