## amyna one year ago the directions to this problem say: "differentiate" u=(arcsinx)^2 i dont understand what the "u" means? Do i just take the derivative as normal by using the chain rule by witting u' ??

1. jim_thompson5910

I think they want you to derive with respect to x. So think of the u as like y ie you have y = (arcsin(x))^2

2. zepdrix

Yes, you have to find u' :)

3. amyna

ok thank guys!

4. amyna

oh ya and for this problem, how do i use the chain rule? f(x)=ln(arctanx)?

5. amyna

alright thanks!

6. zepdrix

$\large\rm f(x)=\ln(\arctan x)$$\large\rm f'(x)=\frac{1}{\arctan x}(\arctan x)'$Yes, chain rule :D Sorry, had to correct my mistake from before lol