amyna
  • amyna
the directions to this problem say: "differentiate" u=(arcsinx)^2 i dont understand what the "u" means? Do i just take the derivative as normal by using the chain rule by witting u' ??
Mathematics
katieb
  • katieb
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jim_thompson5910
  • jim_thompson5910
I think they want you to derive with respect to x. So think of the `u` as like `y` ie you have y = (arcsin(x))^2
zepdrix
  • zepdrix
Yes, you have to find u' :)
amyna
  • amyna
ok thank guys!

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amyna
  • amyna
oh ya and for this problem, how do i use the chain rule? f(x)=ln(arctanx)?
amyna
  • amyna
alright thanks!
zepdrix
  • zepdrix
\[\large\rm f(x)=\ln(\arctan x)\]\[\large\rm f'(x)=\frac{1}{\arctan x}(\arctan x)'\]Yes, chain rule :D Sorry, had to correct my mistake from before lol

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