cutiecomittee123
  • cutiecomittee123
Find the measure of angle b find x find y
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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cutiecomittee123
  • cutiecomittee123
|dw:1441845503857:dw|
jim_thompson5910
  • jim_thompson5910
|dw:1441846059967:dw|
jim_thompson5910
  • jim_thompson5910
using A as a reference angle, we can add these labels |dw:1441846105403:dw|

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More answers

jim_thompson5910
  • jim_thompson5910
find x and y using the trig ratios then find angle B
cutiecomittee123
  • cutiecomittee123
okay
cutiecomittee123
  • cutiecomittee123
i need more pointers, @jim_thompson5910
anonymous
  • anonymous
still doing hw huh
anonymous
  • anonymous
angle b= 165
anonymous
  • anonymous
nvm
anonymous
  • anonymous
im tired.
jim_thompson5910
  • jim_thompson5910
how far did you get @cutiecomittee123 based on the info I posted?
cutiecomittee123
  • cutiecomittee123
no where lol let me try again
cutiecomittee123
  • cutiecomittee123
well i kind of took the easy way out and I just figured there are 180 degrees in a triangle and it is given 90+75 so i added them and got 165 then if you add 15 you get 180 so obviousely angle b is 15 degrees. but then to solve for x and y i can easily see that you just use the trig stuff
jim_thompson5910
  • jim_thompson5910
yes B = 15 degrees
jim_thompson5910
  • jim_thompson5910
how would you find x?
cutiecomittee123
  • cutiecomittee123
I am having a brain fart and cant remeber
jim_thompson5910
  • jim_thompson5910
|dw:1441853405825:dw|
jim_thompson5910
  • jim_thompson5910
which angle do you want to use? A = 75? or B = 15?
cutiecomittee123
  • cutiecomittee123
well lets use B, and wouldnt you use cos because you would do adjacent over hypotenuse? So it would be cos(15)=125/y
jim_thompson5910
  • jim_thompson5910
|dw:1441853613668:dw|
jim_thompson5910
  • jim_thompson5910
cos(B) = adjacent/hypotenuse cos(15) = 125/x now solve for x
cutiecomittee123
  • cutiecomittee123
So wouldnt you take the inverse of both sides?
cutiecomittee123
  • cutiecomittee123
sorry for the super late replies i am also working on a power point.
jim_thompson5910
  • jim_thompson5910
it's ok, work on the powerpoint first and we can work on this later
cutiecomittee123
  • cutiecomittee123
Alright done with the presentation, lets do this:)
jim_thompson5910
  • jim_thompson5910
so you see how I got `cos(15) = 125/x` right?
cutiecomittee123
  • cutiecomittee123
yes
jim_thompson5910
  • jim_thompson5910
using a calculator, what is the value of `cos(15)` equal to (in terms of a decimal number)
cutiecomittee123
  • cutiecomittee123
cos(15)=.97
jim_thompson5910
  • jim_thompson5910
so what we really have is `0.97 = 125/x` are you able to solve that for x?
cutiecomittee123
  • cutiecomittee123
hmm, multiply both sides by x?
jim_thompson5910
  • jim_thompson5910
then what
cutiecomittee123
  • cutiecomittee123
divide by .97
jim_thompson5910
  • jim_thompson5910
yes
cutiecomittee123
  • cutiecomittee123
on both sides
jim_thompson5910
  • jim_thompson5910
what is x equal to
cutiecomittee123
  • cutiecomittee123
x=128.87
jim_thompson5910
  • jim_thompson5910
ok so 125/0.97 = 128.87 is correct it turns out that 125/(cos(15)) = 129.40952255126 is the more accurate answer so it might be best to type into your calculator `125/(cos(15))`
cutiecomittee123
  • cutiecomittee123
okay cool got it, but why would you divide it form 125?
jim_thompson5910
  • jim_thompson5910
\[\Large \cos(15^{\circ}) = \frac{125}{x}\] \[\Large \cos(15^{\circ})\color{red}{*x} = \frac{125}{x}\color{red}{*x}\] \[\Large \cos(15^{\circ})\color{black}{*x} = \frac{125}{\cancel{x}}\color{black}{*\cancel{x}}\] \[\Large \cos(15^{\circ})*x = 125\] \[\Large \frac{\cos(15^{\circ})*x}{\color{red}{\cos(15^{\circ})}} = \frac{125}{\color{red}{\cos(15^{\circ})}}\] \[\Large \frac{\cancel{\cos(15^{\circ})}*x}{\cancel{\cos(15^{\circ})}} = \frac{125}{\color{black}{\cos(15^{\circ})}}\] \[\Large x = \frac{125}{\color{black}{\cos(15^{\circ})}}\]
jim_thompson5910
  • jim_thompson5910
So what I first did was multiply both sides by `x` then I divided both sides by `cos(15)`
cutiecomittee123
  • cutiecomittee123
i see you just solved it like an algebraic equation, basic algebra
jim_thompson5910
  • jim_thompson5910
yeah if you have to, think of `cos(15)` as y so you'd have y = 125/x solving for x gives x = 125/y
cutiecomittee123
  • cutiecomittee123
okay woah, so now y=129.41 and then we can just use the pythagorean theorum to solve for x. so 129.41^2+125^2=x^ added together i get 32302.1396 the square root of that is 179.72796 so x=179.73
jim_thompson5910
  • jim_thompson5910
no, I let y = cos(15) so y = 0.97 like you got, but it's best to leave the cos(15) part alone as it is
jim_thompson5910
  • jim_thompson5910
if you typed 125/cos(15) into a calculator, what do you get?
cutiecomittee123
  • cutiecomittee123
I get 129.41
jim_thompson5910
  • jim_thompson5910
yes, 125/cos(15) = 129.40952255126
cutiecomittee123
  • cutiecomittee123
which is what the side y is equal to
jim_thompson5910
  • jim_thompson5910
oh my bad, I picked y when y is already being used in the drawing
cutiecomittee123
  • cutiecomittee123
yeah lol oops. but yes I think we have it all figured out now. thanks so much!!!!
jim_thompson5910
  • jim_thompson5910
you're welcome

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