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cutiecomittee123

  • one year ago

Find the measure of angle b find x find y

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  1. cutiecomittee123
    • one year ago
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    |dw:1441845503857:dw|

  2. jim_thompson5910
    • one year ago
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    |dw:1441846059967:dw|

  3. jim_thompson5910
    • one year ago
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    using A as a reference angle, we can add these labels |dw:1441846105403:dw|

  4. jim_thompson5910
    • one year ago
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    find x and y using the trig ratios then find angle B

  5. cutiecomittee123
    • one year ago
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    okay

  6. cutiecomittee123
    • one year ago
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    i need more pointers, @jim_thompson5910

  7. anonymous
    • one year ago
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    still doing hw huh

  8. anonymous
    • one year ago
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    angle b= 165

  9. anonymous
    • one year ago
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    nvm

  10. anonymous
    • one year ago
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    im tired.

  11. jim_thompson5910
    • one year ago
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    how far did you get @cutiecomittee123 based on the info I posted?

  12. cutiecomittee123
    • one year ago
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    no where lol let me try again

  13. cutiecomittee123
    • one year ago
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    well i kind of took the easy way out and I just figured there are 180 degrees in a triangle and it is given 90+75 so i added them and got 165 then if you add 15 you get 180 so obviousely angle b is 15 degrees. but then to solve for x and y i can easily see that you just use the trig stuff

  14. jim_thompson5910
    • one year ago
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    yes B = 15 degrees

  15. jim_thompson5910
    • one year ago
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    how would you find x?

  16. cutiecomittee123
    • one year ago
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    I am having a brain fart and cant remeber

  17. jim_thompson5910
    • one year ago
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    |dw:1441853405825:dw|

  18. jim_thompson5910
    • one year ago
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    which angle do you want to use? A = 75? or B = 15?

  19. cutiecomittee123
    • one year ago
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    well lets use B, and wouldnt you use cos because you would do adjacent over hypotenuse? So it would be cos(15)=125/y

  20. jim_thompson5910
    • one year ago
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    |dw:1441853613668:dw|

  21. jim_thompson5910
    • one year ago
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    cos(B) = adjacent/hypotenuse cos(15) = 125/x now solve for x

  22. cutiecomittee123
    • one year ago
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    So wouldnt you take the inverse of both sides?

  23. cutiecomittee123
    • one year ago
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    sorry for the super late replies i am also working on a power point.

  24. jim_thompson5910
    • one year ago
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    it's ok, work on the powerpoint first and we can work on this later

  25. cutiecomittee123
    • one year ago
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    Alright done with the presentation, lets do this:)

  26. jim_thompson5910
    • one year ago
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    so you see how I got `cos(15) = 125/x` right?

  27. cutiecomittee123
    • one year ago
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    yes

  28. jim_thompson5910
    • one year ago
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    using a calculator, what is the value of `cos(15)` equal to (in terms of a decimal number)

  29. cutiecomittee123
    • one year ago
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    cos(15)=.97

  30. jim_thompson5910
    • one year ago
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    so what we really have is `0.97 = 125/x` are you able to solve that for x?

  31. cutiecomittee123
    • one year ago
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    hmm, multiply both sides by x?

  32. jim_thompson5910
    • one year ago
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    then what

  33. cutiecomittee123
    • one year ago
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    divide by .97

  34. jim_thompson5910
    • one year ago
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    yes

  35. cutiecomittee123
    • one year ago
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    on both sides

  36. jim_thompson5910
    • one year ago
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    what is x equal to

  37. cutiecomittee123
    • one year ago
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    x=128.87

  38. jim_thompson5910
    • one year ago
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    ok so 125/0.97 = 128.87 is correct it turns out that 125/(cos(15)) = 129.40952255126 is the more accurate answer so it might be best to type into your calculator `125/(cos(15))`

  39. cutiecomittee123
    • one year ago
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    okay cool got it, but why would you divide it form 125?

  40. jim_thompson5910
    • one year ago
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    \[\Large \cos(15^{\circ}) = \frac{125}{x}\] \[\Large \cos(15^{\circ})\color{red}{*x} = \frac{125}{x}\color{red}{*x}\] \[\Large \cos(15^{\circ})\color{black}{*x} = \frac{125}{\cancel{x}}\color{black}{*\cancel{x}}\] \[\Large \cos(15^{\circ})*x = 125\] \[\Large \frac{\cos(15^{\circ})*x}{\color{red}{\cos(15^{\circ})}} = \frac{125}{\color{red}{\cos(15^{\circ})}}\] \[\Large \frac{\cancel{\cos(15^{\circ})}*x}{\cancel{\cos(15^{\circ})}} = \frac{125}{\color{black}{\cos(15^{\circ})}}\] \[\Large x = \frac{125}{\color{black}{\cos(15^{\circ})}}\]

  41. jim_thompson5910
    • one year ago
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    So what I first did was multiply both sides by `x` then I divided both sides by `cos(15)`

  42. cutiecomittee123
    • one year ago
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    i see you just solved it like an algebraic equation, basic algebra

  43. jim_thompson5910
    • one year ago
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    yeah if you have to, think of `cos(15)` as y so you'd have y = 125/x solving for x gives x = 125/y

  44. cutiecomittee123
    • one year ago
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    okay woah, so now y=129.41 and then we can just use the pythagorean theorum to solve for x. so 129.41^2+125^2=x^ added together i get 32302.1396 the square root of that is 179.72796 so x=179.73

  45. jim_thompson5910
    • one year ago
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    no, I let y = cos(15) so y = 0.97 like you got, but it's best to leave the cos(15) part alone as it is

  46. jim_thompson5910
    • one year ago
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    if you typed 125/cos(15) into a calculator, what do you get?

  47. cutiecomittee123
    • one year ago
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    I get 129.41

  48. jim_thompson5910
    • one year ago
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    yes, 125/cos(15) = 129.40952255126

  49. cutiecomittee123
    • one year ago
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    which is what the side y is equal to

  50. jim_thompson5910
    • one year ago
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    oh my bad, I picked y when y is already being used in the drawing

  51. cutiecomittee123
    • one year ago
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    yeah lol oops. but yes I think we have it all figured out now. thanks so much!!!!

  52. jim_thompson5910
    • one year ago
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    you're welcome

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