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anonymous

  • one year ago

what is the first derivate of x(t)= Et^2 - Ft + G

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  1. anonymous
    • one year ago
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    E and F and G would be constants just like numbers.

  2. Rizags
    • one year ago
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    split it up into derivative of each term

  3. Rizags
    • one year ago
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    differentiate each term individually

  4. anonymous
    • one year ago
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    I had Et + F + G but i was told it is wrong

  5. Rizags
    • one year ago
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    do you know what \[\frac{d}{dt}G\] is, where G is a constant?

  6. anonymous
    • one year ago
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    it becomes zero right ?

  7. Rizags
    • one year ago
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    look, all you need to do is this: \[\frac{d}{dt}Et^2-\frac{d}{dt}Ft+\frac{d}{dt}G\]

  8. Rizags
    • one year ago
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    and yes

  9. anonymous
    • one year ago
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    How did you get +F from a -Ft? It would be a -F instead. Derivative of Et^2 is not Et Use power rule Derivative of \[ax^n\] where a is a constant is \[anx ^{n-1}\]

  10. anonymous
    • one year ago
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    so the answer should be E 2t - F

  11. Rizags
    • one year ago
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    \[\frac{dx}{dt} x(t)=Et^2-Ft+G=2Et-F\]

  12. anonymous
    • one year ago
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    2ET would be better than E2t. Always good to have the number in front.

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