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You might get more help if you post this in the Chemistry section of OpenStudy. :)
But, I know how to balance chemical equations, so let's see;
What do you think the answer is, just be look at the elements on each side?
Let's look at the law of conservation of mass. It states that matter cannot be created nor destroyed. In Chemical reactions, matter cannot be created (Added to the mass of the product that the reactants did not originally have) or destroyed.
KMnO4 + HCl → KCl + MnCl2 + H2O + Cl2 Do you think the product mass is greater than the reactant mass?
In simpler terms, does each side have an equal amount of atoms?
To make it easier, look at each element one by one on both sides of the Reaction to determine if they are equal. That includes Chlorine, Potassium, Hydrogen, and Mn
How many K's are on the left compared to the right?
KMnO4 + HCl → KCl + MnCl2 + H2O + Cl2 Let me break it down a bit for ya. Since there are are 0 coefficients visible in this equation, it is always safe to assume that it the coefficient is 1. The coefficient is what's in front of a molecule or compound, and always affect each element in that compound. The subscript next to each element is the amount of atoms that specific element that it's right next to have. On the left side of the equation, you have KMnO4 + HCl. K has 1 atom since it is no subscript right next to it or coefficient in front of its molecule. So does Mn. O4 has for atoms since it has a 4 subscript next to it. Now we have HCl; H is one hydrogen atom, and Cl is one Chlorine Atom. This is a reactant side. Are you following so far?
For an example of HCl was 2HCl, both H and Cl would have 2 atoms total since the coefficient is two. The coefficient in this hypothetical question, multiplied by the original number of atoms (1 H, 1Cl) would make that reactant have 2 of both Hydrogen and Chlorine.
KCl + MnCl2 + H2O + Cl2, can you count how many atoms each element has seperately? K: Cl Mn: H: O
Where are you confused at?
Where are you confused at?
Let me teach you like my teacher taught me: Imagine that you have a regular Ol' Double Cheeseburger. This Cheeseburger has 2 pieces of bread, 2 hamburger patties, 1 slice of cheese, and One slice a Lettuce. You want to follow this exact recipe using only the ingredients in the Double Cheeseburger that is already so that you already have, so that you can instead make a TRIPLE cheese burger with 3 slices of cheese and 3 hamburger patties. So your first Cheeseburger has 2 pieces of bread, 2 hamburger patties, 1 slice of cheese and One slice of lettuce and 1 piece of lettuce. Can you make a triple cheeseburger given only the ingredients required for this double cheeseburger?
*that you already have*
And only one slice of lettuce. Ignore the double of (One piece of lettuce)
What do you think the answer is to that riddle?
Correcto. Why do you think you can't?
Why is it impossible to make a triple cheeseburger under these conditions?
Your answer is right, but explain why it's correct.
Think of the law of conservation of matter. You can't make a triple cheeseburger under these conditions because you would have to "magically" create another hamburger and slice of cheese, which would be illogical, since you only had 2 slices of cheese and patties to start off with. You understand so far?
That would make the triple cheeseburger weigh more than the double cheeseburger, although you only used the ingredient that the double cheeseburger had.
This same rule applies to Balancing chemical equations. If you start off with one mass, you cannot end up with a different mass, since you only had the reactants at the start of the equaton to work with.
np by the way.
KMnO4 + HCl → KCl + MnCl2 + H2O + Cl2 Lets look back at this equation. Let me help you out. The number of K's on each side is equal to 1. You see exactly 1 K atom on the reactant side of the equation and 1 K on the product side. What about Chlorine and Hydrogen? Is there more Chlorine and hydrogen on the product side of the equation than the Reactant side?