help please :)Students are building a trebuchet for their physics class. The model is shown below. If the length of DA measures 25 inches, then what to the nearest inch is the measure of the support AC?

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help please :)Students are building a trebuchet for their physics class. The model is shown below. If the length of DA measures 25 inches, then what to the nearest inch is the measure of the support AC?

Mathematics
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So just some trig stuff, ya? :)

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okay how would I figure this out?
In relation to our angle, we care about the side `adjacent` (next to it), and the side `opposite` the angle as well.
Which of your three trig functions makes use of `adjacent` and `opposite`? :)
sine cosine tangent?
Yes, those three are the ones we're considering.\[\rm \sin \theta=\frac{opposite}{hypotenuse},\qquad \cos \theta=\frac{adjacent}{hypotenuse},\qquad \tan \theta=\frac{opposite}{adjacent}\]It looks like tangent is the one we want, ya? :D
yes
\[\large\rm \tan\theta=\frac{opposite}{adjacent}\]So we need to plug in the angle and side lengths.\[\large\rm \tan55^o=\frac{x}{25}\]Understand how I was able to set that up? :o
not really
|dw:1441848312912:dw|If our angle is located here in the upper left corner, then our side opposite the angle is over here.
okay yea I do sorry that was so obvious lol
The side we're trying to solve for, I labeled x. So we need to isolate the x. It's being divided by 25. How can we undo that?
Do we divide it by 3?
Sorry it didn't give me the notification D: We're dividing by 25, so let's multiply both sides by 25 to undo that :D
\[\large\rm 25\cdot\tan55^o=\frac{x}{\cancel{25}}\cdot\cancel{25}\]
so I need to multiply 25*55?
No! Be careful not to do that! :) Maybe I should have put brackets around our 55 to be clear. He is the argument of your trig function, he is trapped inside of there. He can't come outside, and the 25 can't come inside. He's grounded :O
\[\large\rm 25\cdot\color{orangered}{\tan(55)}=x\]
You can probably put it into your calculator all at once like that! :) \(\large\rm 25\times\tan(55)\) Make sure you're in `degree mode`!
35?
Yay good job \c:/
Rounded closer to 36 I guess :) But whatever
it wasn't an option but thank you I really didn't understand this but thank you so much for walking me through it. :)

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