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anonymous
 one year ago
help please :)Students are building a trebuchet for their physics class. The model is shown below. If the length of DA measures 25 inches, then what to the nearest inch is the measure of the support AC?
anonymous
 one year ago
help please :)Students are building a trebuchet for their physics class. The model is shown below. If the length of DA measures 25 inches, then what to the nearest inch is the measure of the support AC?

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zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0So just some trig stuff, ya? :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay how would I figure this out?

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0In relation to our angle, we care about the side `adjacent` (next to it), and the side `opposite` the angle as well.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0Which of your three trig functions makes use of `adjacent` and `opposite`? :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sine cosine tangent?

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0Yes, those three are the ones we're considering.\[\rm \sin \theta=\frac{opposite}{hypotenuse},\qquad \cos \theta=\frac{adjacent}{hypotenuse},\qquad \tan \theta=\frac{opposite}{adjacent}\]It looks like tangent is the one we want, ya? :D

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0\[\large\rm \tan\theta=\frac{opposite}{adjacent}\]So we need to plug in the angle and side lengths.\[\large\rm \tan55^o=\frac{x}{25}\]Understand how I was able to set that up? :o

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441848312912:dwIf our angle is located here in the upper left corner, then our side opposite the angle is over here.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay yea I do sorry that was so obvious lol

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0The side we're trying to solve for, I labeled x. So we need to isolate the x. It's being divided by 25. How can we undo that?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Do we divide it by 3?

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0Sorry it didn't give me the notification D: We're dividing by 25, so let's multiply both sides by 25 to undo that :D

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0\[\large\rm 25\cdot\tan55^o=\frac{x}{\cancel{25}}\cdot\cancel{25}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so I need to multiply 25*55?

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0No! Be careful not to do that! :) Maybe I should have put brackets around our 55 to be clear. He is the argument of your trig function, he is trapped inside of there. He can't come outside, and the 25 can't come inside. He's grounded :O

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0\[\large\rm 25\cdot\color{orangered}{\tan(55)}=x\]

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0You can probably put it into your calculator all at once like that! :) \(\large\rm 25\times\tan(55)\) Make sure you're in `degree mode`!

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0Rounded closer to 36 I guess :) But whatever

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it wasn't an option but thank you I really didn't understand this but thank you so much for walking me through it. :)
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