anonymous
  • anonymous
help please :)Students are building a trebuchet for their physics class. The model is shown below. If the length of DA measures 25 inches, then what to the nearest inch is the measure of the support AC?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
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zepdrix
  • zepdrix
|dw:1441847743206:dw|
zepdrix
  • zepdrix
So just some trig stuff, ya? :)

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anonymous
  • anonymous
okay how would I figure this out?
zepdrix
  • zepdrix
In relation to our angle, we care about the side `adjacent` (next to it), and the side `opposite` the angle as well.
zepdrix
  • zepdrix
Which of your three trig functions makes use of `adjacent` and `opposite`? :)
anonymous
  • anonymous
sine cosine tangent?
zepdrix
  • zepdrix
Yes, those three are the ones we're considering.\[\rm \sin \theta=\frac{opposite}{hypotenuse},\qquad \cos \theta=\frac{adjacent}{hypotenuse},\qquad \tan \theta=\frac{opposite}{adjacent}\]It looks like tangent is the one we want, ya? :D
anonymous
  • anonymous
yes
zepdrix
  • zepdrix
\[\large\rm \tan\theta=\frac{opposite}{adjacent}\]So we need to plug in the angle and side lengths.\[\large\rm \tan55^o=\frac{x}{25}\]Understand how I was able to set that up? :o
anonymous
  • anonymous
not really
zepdrix
  • zepdrix
|dw:1441848312912:dw|If our angle is located here in the upper left corner, then our side opposite the angle is over here.
anonymous
  • anonymous
okay yea I do sorry that was so obvious lol
zepdrix
  • zepdrix
The side we're trying to solve for, I labeled x. So we need to isolate the x. It's being divided by 25. How can we undo that?
anonymous
  • anonymous
Do we divide it by 3?
zepdrix
  • zepdrix
Sorry it didn't give me the notification D: We're dividing by 25, so let's multiply both sides by 25 to undo that :D
zepdrix
  • zepdrix
\[\large\rm 25\cdot\tan55^o=\frac{x}{\cancel{25}}\cdot\cancel{25}\]
anonymous
  • anonymous
so I need to multiply 25*55?
zepdrix
  • zepdrix
No! Be careful not to do that! :) Maybe I should have put brackets around our 55 to be clear. He is the argument of your trig function, he is trapped inside of there. He can't come outside, and the 25 can't come inside. He's grounded :O
zepdrix
  • zepdrix
\[\large\rm 25\cdot\color{orangered}{\tan(55)}=x\]
zepdrix
  • zepdrix
You can probably put it into your calculator all at once like that! :) \(\large\rm 25\times\tan(55)\) Make sure you're in `degree mode`!
anonymous
  • anonymous
35?
zepdrix
  • zepdrix
Yay good job \c:/
zepdrix
  • zepdrix
Rounded closer to 36 I guess :) But whatever
anonymous
  • anonymous
it wasn't an option but thank you I really didn't understand this but thank you so much for walking me through it. :)

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