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anonymous
 one year ago
A sample of zinc with a mass of 130.8g contains 6.02 x 10^23 atoms. Calculate the mass of a single zinc atom.
anonymous
 one year ago
A sample of zinc with a mass of 130.8g contains 6.02 x 10^23 atoms. Calculate the mass of a single zinc atom.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ Zn }{ 1 }\times \frac{ grams of one Zn }{ Zn atoms }\] Without numbers, can you figure it out?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0gramsofonezn =grams of one zinc Znatoms= zinc atoms.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Shalante can i try it out and then ask you if it's right? D:

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Sure! I answered your question by the way.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Sorry new to this and okay thanks!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh wait. I thought you were on a different board. I got confused my bad.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I gtg. Be back in 90minutes 1Zn x (130.8g/6.023 x 10^23 Zn atoms.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\sf 130.8~g~Zn ~\times ~\frac{1~mol~ Zn}{65.38 ~g~Zn}~\times \frac{6.02~\times~10^{23}~Zn~atoms}{1~mol~Zn} \]\[\sf = \frac{(130.8 \cdot 6.02~\times~10^{23})}{65.38}~Zn ~atoms \] :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Jhannybean wait where did you get 65.38 from

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Hmm, did I make a mistake? I was helping 4 people at the same time.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I dont think we need molar mass since the grams would cancel out and we need to know the mass of a single Zinc atoms.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Jhannybean Your answer is in Zn atoms. Isnt it supposed to be the gram of one atom?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Maybe it is 130.8g Zn/65.38g Zn=2.00 mol Zn \[\frac{ 2.00 mol Zn }{ 1 }\times \frac{ 6.022\times10^{23} Zn atoms }{ 1mol Zn }=1.2044\times10^{24}Zn atoms\]=1.2044 x 10^24 Zn atoms Divide 130.8 grams by that big number.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Not sure why the question tells us 130.8 g of Zn contains 6.022 x 10^23 atoms. (Is it trying to trick us or is it an exception?)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I think my first formula is right.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0If not, you can blame your teacher because of the bad wording.
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