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Lukecrayonz
 one year ago
If p is true, q is false, and r is false, what is the vaue of (p ^ ~q) ^ r
Lukecrayonz
 one year ago
If p is true, q is false, and r is false, what is the vaue of (p ^ ~q) ^ r

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zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0Then what is ~q? If q is false, then ~q is true, ya? :)

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0truth table might help you get through this one.

Lukecrayonz
 one year ago
Best ResponseYou've already chosen the best response.0I'm trying to help my friend with this but I honestly have never done this, I understand that it is TTF but what makes the final answer true or false?

Lukecrayonz
 one year ago
Best ResponseYou've already chosen the best response.0Such as the next question: if p is true, q is true, and r is true, then what is the value pf (p ^ ~q) ^ r, it would be true, false, true but what would the answer be? True because there are two truths and one false?

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0Umm well if you start in the brackets..\[\large\rm (True\wedge True)\wedge False\]True AND True gives us True. `And` requires that both be true in order to get a true result.\[\large\rm (True)\wedge False\]Again we have AND which is requiring BOTH to be true :O So we get a false as our final result since the requirement wasn't met.

Lukecrayonz
 one year ago
Best ResponseYou've already chosen the best response.0Hmm I was wondering what the brackets meant lol. So for the following question I posted: (true and not true) and true (True and false) would equal out to be false (false) and True would then be false?

Lukecrayonz
 one year ago
Best ResponseYou've already chosen the best response.0Why would the following question be (True ^ True) when there is a not symbol next to q?

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0Oh I guess I misread that :) lol. Good catch

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0`(true AND false) AND true` gave you `(false) AND true` which further gave you `false` yah that sounds right! :)

Lukecrayonz
 one year ago
Best ResponseYou've already chosen the best response.0Oh no @zepdrix D: right when I needed you most haha

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0Sorry I left another gal hangin :d gotta keep jumpin back n forth

Lukecrayonz
 one year ago
Best ResponseYou've already chosen the best response.01: F 2: F Correct so far?

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0True table can be a little tricky. Just need to list every possible combination of true/false for the three letters.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0Ummm, ya that sounds right :D

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.05 minutes? :p oh boy that doesn't give su much to work with lol

Lukecrayonz
 one year ago
Best ResponseYou've already chosen the best response.0So basically anytime there is a false such as ~true which would be false ^ (true) So the line would be False ^ True its always false since I guess the false would overpower the true? Lol

Lukecrayonz
 one year ago
Best ResponseYou've already chosen the best response.0And if the answer is False ^ False, the answer is False?

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0It's not so much that it "overpowers" it. It's the fact that `AND` is a very strict requirement. `AND` is asking the question "ARE BOTH OF THESE THINGS TRUE?"

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0Correct False AND False gives a False result because we need both True to end up with True.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0False ^ True => False True ^ False => False False ^ False => False True ^ True => True
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