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amyna
 one year ago
find the intergal:
Don't know what "u" is in this problem?
amyna
 one year ago
find the intergal: Don't know what "u" is in this problem?

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jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1let `u = arctan(x)` then `du/dx = 1/(1+x^2)` > `du = dx/(1+x^2)`

amyna
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441849417744:dw i got this, then i don't know what to do?

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2I like to break it up like this :)\[\large\rm \int\limits \frac{\arctan x}{1+x^2}dx=\int\limits \color{royalblue}{\arctan x}\left(\color{orangered}{\frac{1}{1+x^2}dx}\right)\]Maybe the colors will help you to see what is going on.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2You decided that,\[\large\rm \color{royalblue}{u=\arctan x},\qquad\qquad du=?\]

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2Good. Don't forget about your differential though! :)

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2\[\large\rm \color{royalblue}{u=\arctan x},\qquad\qquad \color{orangered}{du=\frac{1}{1+x^2}dx}\]

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2\[\large\rm \int\limits\limits \color{royalblue}{\arctan x}\left(\color{orangered}{\frac{1}{1+x^2}dx}\right)=\int\limits\limits \color{royalblue}{u}\left(\color{orangered}{du}\right)\]Did the colors help? :o Not so much?

amyna
 one year ago
Best ResponseYou've already chosen the best response.0is the answer arctan^2(x)/2 }+c?
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