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anonymous

  • one year ago

Can someone please help me figure out how to do parts b and c on this? A to B is a straight horizontal portion of length x and B to C is a quarter of a circle with radius r. The particle P starts from rest at point A at time t = 0 and changes its speed thereafter at a constant rate of 2.4g as it follows the horizontal path shown. Determine the magnitude and direction of its total acceleration (a) just before point B, (b) just after point B, and (c) as it passes point C.

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  1. anonymous
    • one year ago
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  2. anonymous
    • one year ago
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  3. BAdhi
    • one year ago
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    jst before point be the acceleration will be the same as the acceleration when the object start to move. That is 2.4g But after the point B, it follows a circular motion, with the linear acceleration. Therefore there are two acceleration components. the linear acceleration component will not change from 2.4g, and the centripetal acceleration can be found by using \(\frac{v^2}{r}\).

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