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## anonymous one year ago Help with limits for a medal?

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1. Jhannybean

No question.

2. anonymous

Im attaching the file

3. anonymous

4. zzr0ck3r

Still no question

5. anonymous

Use the graph to find the limit and determine the continuity of the function.

6. anonymous

Sorry about that. My internet is giving me some troubles.

7. zzr0ck3r

What limit?

8. zzr0ck3r

np the servers here are funny sometimes.

9. anonymous

Just a sec. It's not letting me post them

10. anonymous

Hah! Got it!

11. zzr0ck3r

Right, this is what I figured. Ok as you walk along the graph from left to right there is an obvious problem at $$x=-1$$. What value do you approach(y value) as you get closer to $$x=-1$$

12. anonymous

There's a hole in the graph

13. zzr0ck3r

what value is y when you approach from the left?

14. anonymous

2

15. zzr0ck3r

so $$\lim_{x\rightarrow c^{-}}f(x)=2$$ What about from the right?

16. anonymous

It gets closer to 0

17. zzr0ck3r

Yep so $$\lim_{x\rightarrow 2^{+}}f(x)=0$$

18. zzr0ck3r

now does $$2\ne 0$$?

19. anonymous

Yes, 2 doesn't equal zero.

20. zzr0ck3r

obviously not, thus $$\lim_{x\rightarrow c}f(x)$$ does not exist

21. anonymous

That was much easier than I expected.

22. zzr0ck3r

now, since we cant just fill in one point and make it continuous, i.e. there is no one point that we can add so that we can draw the entire graph without lifting the pencil and thus is does not have a removable discontinuity .

23. anonymous

I see now. Thank you! :)

24. zzr0ck3r

np

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