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anonymous

  • one year ago

How many three different digit numbers can be formed using the digits 2,3,5,6,7. ASAP with process

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  1. zzr0ck3r
    • one year ago
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    can we repeat?

  2. anonymous
    • one year ago
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    We have to find how many of 3-digit numbers can be formed by using 2,3,5,6,7. When every digit should be different in the number

  3. anonymous
    • one year ago
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    In the first digit you can have 5 different numbers (all the digits), then in the second you can have 5-1=4 possible numbers because it cannot be equal to the first digit. Then in the third digit you are left with only 4-1=3 possible digits because two of them have been already used in the first two places. Therefore 5x4x3=60 possible combinations.

  4. madhu.mukherjee.946
    • one year ago
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    Using permutation you can solve this problem as - First place can be filled with 5 ways Second place can be filled with 4 ways Third place can be filled with 3 ways So ,answer is 5*4*3=60

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