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anonymous
 one year ago
How many three different digit numbers can be formed using the digits 2,3,5,6,7. ASAP with process
anonymous
 one year ago
How many three different digit numbers can be formed using the digits 2,3,5,6,7. ASAP with process

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0We have to find how many of 3digit numbers can be formed by using 2,3,5,6,7. When every digit should be different in the number

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0In the first digit you can have 5 different numbers (all the digits), then in the second you can have 51=4 possible numbers because it cannot be equal to the first digit. Then in the third digit you are left with only 41=3 possible digits because two of them have been already used in the first two places. Therefore 5x4x3=60 possible combinations.

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0Using permutation you can solve this problem as  First place can be filled with 5 ways Second place can be filled with 4 ways Third place can be filled with 3 ways So ,answer is 5*4*3=60
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