anonymous
  • anonymous
How many three different digit numbers can be formed using the digits 2,3,5,6,7. ASAP with process
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
zzr0ck3r
  • zzr0ck3r
can we repeat?
anonymous
  • anonymous
We have to find how many of 3-digit numbers can be formed by using 2,3,5,6,7. When every digit should be different in the number
anonymous
  • anonymous
In the first digit you can have 5 different numbers (all the digits), then in the second you can have 5-1=4 possible numbers because it cannot be equal to the first digit. Then in the third digit you are left with only 4-1=3 possible digits because two of them have been already used in the first two places. Therefore 5x4x3=60 possible combinations.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

madhu.mukherjee.946
  • madhu.mukherjee.946
Using permutation you can solve this problem as - First place can be filled with 5 ways Second place can be filled with 4 ways Third place can be filled with 3 ways So ,answer is 5*4*3=60

Looking for something else?

Not the answer you are looking for? Search for more explanations.