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Pulsified333

  • one year ago

Assume that the lottery pays $10 on one play out of 100, it pays $2000 on one play out of 7,500, and it pays $12500 on one play out of 150,000. What probability should be assigned to a ticket's not winning anything?

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  1. Pulsified333
    • one year ago
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    @iLoatheMath do you know how to do this?

  2. anonymous
    • one year ago
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    I would assume you divide them to find the probability? Hmm..

  3. Pulsified333
    • one year ago
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    divide what?

  4. anonymous
    • one year ago
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    I am probably doing this all wrong...is there multiple choice?

  5. Pulsified333
    • one year ago
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    no

  6. anonymous
    • one year ago
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    Probability = the number of outcomes that are possible for the terms provided divided by the total number of outcomes possible.

  7. anonymous
    • one year ago
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    Have you watched khan academy videos possibly? Those usually help me.

  8. Pulsified333
    • one year ago
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    no I havent

  9. anonymous
    • one year ago
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    I haven't got the slightest clue how to solve this..I would assume you divide each individual one by how much $ lottery gets. This is statistics isn't it? I took Calculus!);

  10. Pulsified333
    • one year ago
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    its finite

  11. anonymous
    • one year ago
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    Oh

  12. kropot72
    • one year ago
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    The probability of winning a prize is given by: \[\large \frac{1}{100}+\frac{1}{7500}+\frac{1}{150000}=\frac{1521}{150000}\] Therefore the probability of a ticket's not winning anything is: \[\large 1-\frac{1521}{150000}=\frac{148479}{150000}\]

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