## Pulsified333 one year ago Assume that the lottery pays $10 on one play out of 100, it pays$2000 on one play out of 7,500, and it pays $12500 on one play out of 150,000. What probability should be assigned to a ticket's not winning anything? • This Question is Closed 1. Pulsified333 @iLoatheMath do you know how to do this? 2. anonymous I would assume you divide them to find the probability? Hmm.. 3. Pulsified333 divide what? 4. anonymous I am probably doing this all wrong...is there multiple choice? 5. Pulsified333 no 6. anonymous Probability = the number of outcomes that are possible for the terms provided divided by the total number of outcomes possible. 7. anonymous Have you watched khan academy videos possibly? Those usually help me. 8. Pulsified333 no I havent 9. anonymous I haven't got the slightest clue how to solve this..I would assume you divide each individual one by how much$ lottery gets. This is statistics isn't it? I took Calculus!);

10. Pulsified333

its finite

11. anonymous

Oh

12. kropot72

The probability of winning a prize is given by: $\large \frac{1}{100}+\frac{1}{7500}+\frac{1}{150000}=\frac{1521}{150000}$ Therefore the probability of a ticket's not winning anything is: $\large 1-\frac{1521}{150000}=\frac{148479}{150000}$