Pulsified333
  • Pulsified333
Assume that the lottery pays $10 on one play out of 100, it pays $2000 on one play out of 7,500, and it pays $12500 on one play out of 150,000. What probability should be assigned to a ticket's not winning anything?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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Pulsified333
  • Pulsified333
@iLoatheMath do you know how to do this?
anonymous
  • anonymous
I would assume you divide them to find the probability? Hmm..
Pulsified333
  • Pulsified333
divide what?

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More answers

anonymous
  • anonymous
I am probably doing this all wrong...is there multiple choice?
Pulsified333
  • Pulsified333
no
anonymous
  • anonymous
Probability = the number of outcomes that are possible for the terms provided divided by the total number of outcomes possible.
anonymous
  • anonymous
Have you watched khan academy videos possibly? Those usually help me.
Pulsified333
  • Pulsified333
no I havent
anonymous
  • anonymous
I haven't got the slightest clue how to solve this..I would assume you divide each individual one by how much $ lottery gets. This is statistics isn't it? I took Calculus!);
Pulsified333
  • Pulsified333
its finite
anonymous
  • anonymous
Oh
kropot72
  • kropot72
The probability of winning a prize is given by: \[\large \frac{1}{100}+\frac{1}{7500}+\frac{1}{150000}=\frac{1521}{150000}\] Therefore the probability of a ticket's not winning anything is: \[\large 1-\frac{1521}{150000}=\frac{148479}{150000}\]

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