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anonymous
 one year ago
Let
X=(a,b,c,d,e)andτ=(X,ϕ,[a],[c,d],[a,c,d],[b,c,d,e]).LetA=[a,c]
, then set
A′of limit points of A
is given by
anonymous
 one year ago
Let X=(a,b,c,d,e)andτ=(X,ϕ,[a],[c,d],[a,c,d],[b,c,d,e]).LetA=[a,c] , then set A′of limit points of A is given by

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0A′=(b,c,e) A′=(b,d,e) A′=(b,e) A′=X

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.3Do you mean interval [ ] ?

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.3do you mean the empty set \(\emptyset\) and not that weird thing?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i think {} and that weird thing is empty set

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.3ok can you edit it to make sense?

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.3these things mean different things...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0X=(a,b,c,d,e)andτ=(X,ϕ,{a},{c,d},{a,c,d},{b,c,d,e}).LetA={a,c} , then set A′ of limit points of A is given by

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0because that is A complement with X

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.3So you think that the set of limit points is defined to be the compliment?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0please i will be happy if you explain the concept with you

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.3What is a limit point?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it is the boundary points or closed interval points

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.3So you did not read a thing I wrote on the last problem?

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.3Go back and read that and then tell me what a limit point is

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0a point for which every neighborhood contains at least one point belonging to a given set.

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.3Also, when you reply to something I have commented on, I get tagged and see it. There is no reason to tag me more than once on a post.

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.3ok, so what are the open sets containing b?

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.3does that intersect A? in other words, does that share any points with A?

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.3ok, what are the open sets containing d?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0{c,d},{a,c,d},{b,c,d,e}

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.3I shuold be saying intersect A at some other point...

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.3ok do all of those sets intersect A at some other point other than d?

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.3why are you using caps?

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.3d is not in A... try again

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sorry . 'a' for the first and 'c' for the second and third

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.3ok and with e we get the same thing as with b right?

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.3So your option is looking good, but maybe some other point is also a limit point. What open sets contain a?

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.3Better yet, do all of the open sets that contain a also intersect A at some point other than a?

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.3do all of the open sets that contain a also intersect A at some point other than a?

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.3right so you mean no then?

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.3then a is not a limit point what about c?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes ,{a,c,d} because it intersects A

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.3is that the only open set that contains c? Remember, we only have to find one that does not intersect at some point other than c

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0,{c,d},{a,c,d},{b,c,d,e} contain c

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.3do all of those intersect A at some point different than c?

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.3so there is at least one that does not?

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.3then c is NOT a limit point. So yes your option B is the answer, but not for the reason you listed :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok. thanks . i have to view this page more often to understand this

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Let A=(0,1]⋃2 be a subset of R

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what are the limit points

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.3remember to show something is not a limit points you need to show that it has an open set around it that intersects the set at some point OTHER than the point in question. I did not stress that in the last post.

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.3For a subset \(A\subset X\) a limit point \(x\) of \(A\) is a point in \(X\) (not necessarily in \(A\)) such that all open sets containing it intersect \(A\) at some point other than \(x\).

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.3you think what 0 and 1?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Let A=(0,1]⋃2 be a subset of R
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