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anonymous
 one year ago
How do I find the limit of (x+3)^2 if x is approaching negative 4?
anonymous
 one year ago
How do I find the limit of (x+3)^2 if x is approaching negative 4?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0This is a polynomial, so you can use direct substitution. Plug in 4 for x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No foiling is required for the polynomial before plugging it in?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you can, but it's not necessary. You'll get the same value regardless

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay, I just wanted to make sure I wasn't doing unnecessary steps. May I ask another quick question?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0If I'm just finding the limit, I just plug the value x is approaching into the limit. So, for the limit (x/(x^2+4)) with x approaching 1. I would just plug in the value of 1 for x without any other steps?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes you can just plug in for that limit, but that doesn't always work, especially for rational functions

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so sometimes you will have to factor or do some other type of algebra, but it really depends on the function and the value of x it's approaching

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Do you perhaps have an example of when factoring would be required?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\lim_{x \rightarrow 2}\frac{ x+2 }{ x^24 }\] Plugging in 2 makes the denominator be 0. \[\lim_{x \rightarrow 2}\frac{ x+2 }{ (x+2)(x2) }\] Cancel \[\lim_{x \rightarrow 2}\frac{ 1 }{ (x2) }\] Now plug in to get \(\frac{ 1 }{ 4 }\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I have a problem right now that wishes for me to write a simpler function that agrees with the given function at all but one point. Then to find the limit of that function. The limit as x approaches 0 of the limit (x^2+3x)/x.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm not entirely sure what they mean by a simpler function, unless they would like me to factor out the x values to cancel out the x's.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do you know what a piecewise function is?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I haven't used a piecewise function in awhile, if you could explain it to me, I'd very much appreciate it.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the ones that look like this, with two different functions for different parts of the domain dw:1441887942891:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh wait, no you don't need that. I misread the question. All they want you to do is factor and cancel the x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay, I thought so. Do you know when to classify when a limit is going to be a piecewise function?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You won't need to write as a piecewise function for taking a limit. I thought it was asking you to write that function as a continuous function. It has a hole at 0, so I you'd use a piecewise function to fill the hole.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so, i have a limit as x approaches two and my function is (X^38)/(x2) and I'm not entirely sure what to do. I have the same guidelines as the previous problem.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0factor the numerator using the difference of cubes, and the (x2) will cancel in the denominator.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm terribly sorry for asking, but could you reteach me how to factor cubes?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[(a^3 \pm b^^3)=(a \pm b)(a^2 \mp ab + b^2)\] You can use the SOAP mnemonic to remember the signs, Same, Opposite, Always Positive For \(x^38\), \(a = x\) and \(b = 2\) so it factors to \((x  2)(x^2+2x+4)\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[(a^3 \pm b^3)=(a \pm b)(a^2 \mp ab + b^2)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you, I'll write down that formula and mnemonic to remember!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I think I have it from here! Thank you so much for all your help!
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