slayer8001
  • slayer8001
Solve the inequality 2x - 3 < x + 2 ≤ 3x + 5. Show your work.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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slayer8001
  • slayer8001
@peachpi
slayer8001
  • slayer8001
plz I really need help
anonymous
  • anonymous
break this up. Do this one first \[2x-3 < x + 2\]

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More answers

slayer8001
  • slayer8001
is it -1x<2x ?
slayer8001
  • slayer8001
@peachpi
anonymous
  • anonymous
|dw:1441890766597:dw|
anonymous
  • anonymous
then do \(x+2 \le 3x+5\)
anonymous
  • anonymous
start by subtracting 3x from both sides
slayer8001
  • slayer8001
it would be the same wouldn't it?
anonymous
  • anonymous
usually not.
slayer8001
  • slayer8001
is it -2+2<5?
slayer8001
  • slayer8001
after subtracting 3
anonymous
  • anonymous
where did your x go? You should have -2x + 2 < 5 Then subtract the 2 from both sides
slayer8001
  • slayer8001
oops yeah forgot to put the x
slayer8001
  • slayer8001
-2x<3?
anonymous
  • anonymous
right then divide by -2 and flip the sign since it's negative
slayer8001
  • slayer8001
-1x>0.67?
anonymous
  • anonymous
x > -0.67 b/c you only flip once you divide by the negative
anonymous
  • anonymous
also, you should leave it as \(x>-\frac{2}{3}\) because it's more exact
slayer8001
  • slayer8001
ok
anonymous
  • anonymous
If you were to graph the two solutions it would look like this|dw:1441891511708:dw|
anonymous
  • anonymous
But your final answer combines them|dw:1441891692074:dw|
anonymous
  • anonymous
So the solution is all numbers between -2/3 and 5, including 5 and you'd write it as \[-\frac{ 2 }{ 3 }
slayer8001
  • slayer8001
ok thanks so much I really appreciate your help
anonymous
  • anonymous
you're welcome

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