anonymous
  • anonymous
Any help would be great: Function Notation If ƒ(x ) = x 2 + 1 and g(x ) = 3x + 1, find 2 · ƒ(4).
Mathematics
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chestercat
  • chestercat
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misty1212
  • misty1212
HI!!
anonymous
  • anonymous
Hi
misty1212
  • misty1212
are you looking for \[2\times f(4)\]?

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anonymous
  • anonymous
Those values are subbed into the expression
anonymous
  • anonymous
*equation
misty1212
  • misty1212
there is not \(g\) in this your main job is to find \[f(4)=4^2+1\]
misty1212
  • misty1212
then multiply the result by 2
misty1212
  • misty1212
you got that?
misty1212
  • misty1212
\[f(x)=^2+1\\ f(4)=4^2+1=17\\ 2f(4)=2\times 17\]
anonymous
  • anonymous
So 34. Why would you not add g of x?
misty1212
  • misty1212
you asked for \[2f(4)\]right?
misty1212
  • misty1212
got no \(g\) in it
anonymous
  • anonymous
That is where I reached my snag there was no x value so I assumed you simplified.
misty1212
  • misty1212
lol there is no such thing as "simplify"
misty1212
  • misty1212
add, subtract, multiply, divide, combine like terms, reduce to lowest terms, write in simplest radical form etc. but not "simplify"
anonymous
  • anonymous
Great so I just have to solve for F(X)?
anonymous
  • anonymous
My original question was just what was on my paper.
anonymous
  • anonymous
So another example. If ƒ(x ) = x 2 + 1 and g(x ) = 3x + 1, find [ƒ(4)] 2. Would just be 257?
anonymous
  • anonymous
x^2 and [f(4)] ^ 2
beginnersmind
  • beginnersmind
well f(4) is 17. So [f(4)]^2 is 17^2.
beginnersmind
  • beginnersmind
Or did you change the definition of f(x) to f(x) = x^2? Then [f(4)]^2 = (4^2)^2 = 16^2 = 256

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