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anonymous

  • one year ago

Any help would be great: Function Notation If ƒ(x ) = x 2 + 1 and g(x ) = 3x + 1, find 2 · ƒ(4).

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  1. misty1212
    • one year ago
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    HI!!

  2. anonymous
    • one year ago
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    Hi

  3. misty1212
    • one year ago
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    are you looking for \[2\times f(4)\]?

  4. anonymous
    • one year ago
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    Those values are subbed into the expression

  5. anonymous
    • one year ago
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    *equation

  6. misty1212
    • one year ago
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    there is not \(g\) in this your main job is to find \[f(4)=4^2+1\]

  7. misty1212
    • one year ago
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    then multiply the result by 2

  8. misty1212
    • one year ago
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    you got that?

  9. misty1212
    • one year ago
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    \[f(x)=^2+1\\ f(4)=4^2+1=17\\ 2f(4)=2\times 17\]

  10. anonymous
    • one year ago
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    So 34. Why would you not add g of x?

  11. misty1212
    • one year ago
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    you asked for \[2f(4)\]right?

  12. misty1212
    • one year ago
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    got no \(g\) in it

  13. anonymous
    • one year ago
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    That is where I reached my snag there was no x value so I assumed you simplified.

  14. misty1212
    • one year ago
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    lol there is no such thing as "simplify"

  15. misty1212
    • one year ago
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    add, subtract, multiply, divide, combine like terms, reduce to lowest terms, write in simplest radical form etc. but not "simplify"

  16. anonymous
    • one year ago
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    Great so I just have to solve for F(X)?

  17. anonymous
    • one year ago
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    My original question was just what was on my paper.

  18. anonymous
    • one year ago
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    So another example. If ƒ(x ) = x 2 + 1 and g(x ) = 3x + 1, find [ƒ(4)] 2. Would just be 257?

  19. anonymous
    • one year ago
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    x^2 and [f(4)] ^ 2

  20. beginnersmind
    • one year ago
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    well f(4) is 17. So [f(4)]^2 is 17^2.

  21. beginnersmind
    • one year ago
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    Or did you change the definition of f(x) to f(x) = x^2? Then [f(4)]^2 = (4^2)^2 = 16^2 = 256

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