anonymous
  • anonymous
Just checking. If ƒ(x ) = x 2 + 1 and g(x ) = 3x + 1, find 2ƒ(1) + 3g(4).
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
I came up with 42. Is that correct?
beginnersmind
  • beginnersmind
That's not what I got. What did you get for 2f(1) and 3g(4)?
anonymous
  • anonymous
5 and 37

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More answers

beginnersmind
  • beginnersmind
Hm. 2f(1) is 2*(f(1)) or 2 times the value of the function f(x) at 1.
beginnersmind
  • beginnersmind
So you should start by calculating f(1) and g(4), by plugging x=1 into f(x) and x=4 into g(x). Is that what you did?
anonymous
  • anonymous
Yes.
anonymous
  • anonymous
What was your final answer? Maybe I can plug it in and see if it is a match.
beginnersmind
  • beginnersmind
The final answer is 43. f(1) = 2 2f(1) =4 g(4) = 13 3g(4) = 39
beginnersmind
  • beginnersmind
I'm guessing x2 meant x^2 in your problem, not 2x.
anonymous
  • anonymous
right. did you do 13*3
beginnersmind
  • beginnersmind
Yes.
anonymous
  • anonymous
I think I got it thanks.
beginnersmind
  • beginnersmind
No problem. If you need to go through a few more I'll be happy to help.
anonymous
  • anonymous
Alright. If ƒ(x ) = x^2 + 1 and g(x ) = 3x + 1, find [ƒ(2) - g(1)]^2.
beginnersmind
  • beginnersmind
Alright, start by calculating f(2) and g(1)
anonymous
  • anonymous
5 and 4
beginnersmind
  • beginnersmind
|dw:1441895933081:dw|
beginnersmind
  • beginnersmind
right
anonymous
  • anonymous
when does the exponent outside of the bracket come into play
anonymous
  • anonymous
5-4=1 1^2 is 1
beginnersmind
  • beginnersmind
Correct. The exponent "comes into play" when you calculate what's the value of the base. (that is the expression inside the [ ] parentheses.)
anonymous
  • anonymous
How about If ƒ(x ) = x^2 + 1, find ƒ(a + 1).
anonymous
  • anonymous
(a+1)^2 + 1
beginnersmind
  • beginnersmind
That's essentially correct.
beginnersmind
  • beginnersmind
You can write it out as a^2 + 2a + 2, if you want.
anonymous
  • anonymous
Given the function ƒ(x ) = 3x + 1, evaluate ƒ(a + 1) Could you use distributive So 3(a+1)+1 becomes 3a+3+1 then 3a+4
beginnersmind
  • beginnersmind
Yes.
anonymous
  • anonymous
Great last one.If ƒ(x ) = 3x + 1, then ƒ(a + h ) - ƒ(a ) =
anonymous
  • anonymous
3h
beginnersmind
  • beginnersmind
After you get the result f(a+1) = 3(a+1) + 1 you can treat the result as any other expression.
beginnersmind
  • beginnersmind
Great last one.If ƒ(x ) = 3x + 1, then ƒ(a + h ) - ƒ(a ) = 3h correct
anonymous
  • anonymous
Thank you. You have been such a great help.
beginnersmind
  • beginnersmind
Cool :)

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