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anonymous
 one year ago
Just checking.
If ƒ(x ) = x 2 + 1 and g(x ) = 3x + 1, find 2ƒ(1) + 3g(4).
anonymous
 one year ago
Just checking. If ƒ(x ) = x 2 + 1 and g(x ) = 3x + 1, find 2ƒ(1) + 3g(4).

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I came up with 42. Is that correct?

beginnersmind
 one year ago
Best ResponseYou've already chosen the best response.1That's not what I got. What did you get for 2f(1) and 3g(4)?

beginnersmind
 one year ago
Best ResponseYou've already chosen the best response.1Hm. 2f(1) is 2*(f(1)) or 2 times the value of the function f(x) at 1.

beginnersmind
 one year ago
Best ResponseYou've already chosen the best response.1So you should start by calculating f(1) and g(4), by plugging x=1 into f(x) and x=4 into g(x). Is that what you did?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What was your final answer? Maybe I can plug it in and see if it is a match.

beginnersmind
 one year ago
Best ResponseYou've already chosen the best response.1The final answer is 43. f(1) = 2 2f(1) =4 g(4) = 13 3g(4) = 39

beginnersmind
 one year ago
Best ResponseYou've already chosen the best response.1I'm guessing x2 meant x^2 in your problem, not 2x.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0right. did you do 13*3

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I think I got it thanks.

beginnersmind
 one year ago
Best ResponseYou've already chosen the best response.1No problem. If you need to go through a few more I'll be happy to help.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Alright. If ƒ(x ) = x^2 + 1 and g(x ) = 3x + 1, find [ƒ(2)  g(1)]^2.

beginnersmind
 one year ago
Best ResponseYou've already chosen the best response.1Alright, start by calculating f(2) and g(1)

beginnersmind
 one year ago
Best ResponseYou've already chosen the best response.1dw:1441895933081:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0when does the exponent outside of the bracket come into play

beginnersmind
 one year ago
Best ResponseYou've already chosen the best response.1Correct. The exponent "comes into play" when you calculate what's the value of the base. (that is the expression inside the [ ] parentheses.)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0How about If ƒ(x ) = x^2 + 1, find ƒ(a + 1).

beginnersmind
 one year ago
Best ResponseYou've already chosen the best response.1That's essentially correct.

beginnersmind
 one year ago
Best ResponseYou've already chosen the best response.1You can write it out as a^2 + 2a + 2, if you want.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Given the function ƒ(x ) = 3x + 1, evaluate ƒ(a + 1) Could you use distributive So 3(a+1)+1 becomes 3a+3+1 then 3a+4

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Great last one.If ƒ(x ) = 3x + 1, then ƒ(a + h )  ƒ(a ) =

beginnersmind
 one year ago
Best ResponseYou've already chosen the best response.1After you get the result f(a+1) = 3(a+1) + 1 you can treat the result as any other expression.

beginnersmind
 one year ago
Best ResponseYou've already chosen the best response.1Great last one.If ƒ(x ) = 3x + 1, then ƒ(a + h )  ƒ(a ) = 3h correct

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you. You have been such a great help.
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