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kaylaprincess
 one year ago
I dont understand :\
What is NOT a restriction of the product of quantity x squared plus 3 x plus 2 divided by quantity x squared minus 2 x minus 3 multiplied by quantity x squared plus 4 x pl ? (2 points)
kaylaprincess
 one year ago
I dont understand :\ What is NOT a restriction of the product of quantity x squared plus 3 x plus 2 divided by quantity x squared minus 2 x minus 3 multiplied by quantity x squared plus 4 x pl ? (2 points)

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kaylaprincess
 one year ago
Best ResponseYou've already chosen the best response.0\[ \frac{ 3x + 12x + 9 }{ x^2  4 } \div \frac{ 4x + 4 }{ x + 2 }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Because this is division, you have to flip the 2nd fraction and change it to multiplication. \[\frac{ 3x + 12x + 9 }{ x^2  4 } \times \frac{ x+2 }{ 4x+4 }\] You have to solve for the restrictions to find numbers that are NOT restrictions. The restrictions are any numbers that make the denominator 0. So you have to solve these two equations to get the restrictions \(x^24=0\) and \(4x+4=0\)

kaylaprincess
 one year ago
Best ResponseYou've already chosen the best response.0would it be 4? as the restriction?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no, you can always test your options in the denominators. If you get 0, it's a restriction

kaylaprincess
 one year ago
Best ResponseYou've already chosen the best response.0i still feel confused.

kaylaprincess
 one year ago
Best ResponseYou've already chosen the best response.0does the number have to be same to be the restriction to both?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0not necessarily. each fraction will have it's own restriction. The restrictions for the whole problem will be all of them combined

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441898895861:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ALL other numbers are NOT restrictions

kaylaprincess
 one year ago
Best ResponseYou've already chosen the best response.0I see and understand this so much better now, thank you for your time and help!
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