Goose.
  • Goose.
Find the solution of 4 times the square root of the quantity of x plus 2 equals negative 16, and determine if it is an extraneous solution. x = 14; not extraneous x = 2; extraneous x = 2; not extraneous x = 14; extraneous
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Goose.
  • Goose.
\[4\sqrt{x+2}=-16\]
anonymous
  • anonymous
any ideas on how to start?
Goose.
  • Goose.
You would move -16 to the left side, and set it equal to 0?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
I'd divide by the 4.
anonymous
  • anonymous
It's not a polynomial, so you don't have to set it equal to 0
Goose.
  • Goose.
So I'd have? \[\frac{ \sqrt{x+2} }{ 4 }=-4\]
anonymous
  • anonymous
|dw:1441897429536:dw|
Goose.
  • Goose.
OH yeah, the 4 cancel eachother out on the left side,
anonymous
  • anonymous
ok. so the everything left on the left side is under the radical, and the number on the right side is negative, so this equation has no real solution. And the solution must be extraneous
anonymous
  • anonymous
because you can't take a square root and get a negative number as the result
Goose.
  • Goose.
Okay,
anonymous
  • anonymous
next is to square both sides
Goose.
  • Goose.
So x + 2 = 16
anonymous
  • anonymous
right
Goose.
  • Goose.
Then you isolate your variable, to make it x = 14, extraneous.
Goose.
  • Goose.
Thanks :)
anonymous
  • anonymous
you're welcome
radar
  • radar
What would be the results, if you divided both sides by a -4?|dw:1441898080802:dw|
radar
  • radar
Squaring both sides getting: x+2 = 16 x=14 \[4\sqrt{14 + 2}=-16\]\[4\sqrt{16}=-16\]\[4\times \pm4=\pm16\]\[\pm16=\pm16\] If we accept that the square root of 16 is a plus or minus 4, then it would seem that 14 is not extraneous Hmmmmm
radar
  • radar
With that I will log off and do some review.....

Looking for something else?

Not the answer you are looking for? Search for more explanations.