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anonymous
 one year ago
Find the solution of 4 times the square root of the quantity of x plus 2 equals negative 16, and determine if it is an extraneous solution.
x = 14; not extraneous
x = 2; extraneous
x = 2; not extraneous
x = 14; extraneous
anonymous
 one year ago
Find the solution of 4 times the square root of the quantity of x plus 2 equals negative 16, and determine if it is an extraneous solution. x = 14; not extraneous x = 2; extraneous x = 2; not extraneous x = 14; extraneous

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0any ideas on how to start?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You would move 16 to the left side, and set it equal to 0?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'd divide by the 4.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It's not a polynomial, so you don't have to set it equal to 0

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So I'd have? \[\frac{ \sqrt{x+2} }{ 4 }=4\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441897429536:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0OH yeah, the 4 cancel eachother out on the left side,

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok. so the everything left on the left side is under the radical, and the number on the right side is negative, so this equation has no real solution. And the solution must be extraneous

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0because you can't take a square root and get a negative number as the result

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0next is to square both sides

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Then you isolate your variable, to make it x = 14, extraneous.

radar
 one year ago
Best ResponseYou've already chosen the best response.0What would be the results, if you divided both sides by a 4?dw:1441898080802:dw

radar
 one year ago
Best ResponseYou've already chosen the best response.0Squaring both sides getting: x+2 = 16 x=14 \[4\sqrt{14 + 2}=16\]\[4\sqrt{16}=16\]\[4\times \pm4=\pm16\]\[\pm16=\pm16\] If we accept that the square root of 16 is a plus or minus 4, then it would seem that 14 is not extraneous Hmmmmm

radar
 one year ago
Best ResponseYou've already chosen the best response.0With that I will log off and do some review.....
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