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What do u think the answer is ?
Honestly, I don't know, I know that 3 mol of Nitrogen has the potential to produce 102.24 g of NH3 and that 5 moles of Hydrogen has the potential to produce 56.8 grams of NH3, but I don't know how to figure out how many moles of nitrogen will be left over after the reaction.
According to the equation we can see that 1 mole of nitrogen reacts with 3 moles of hydrogen right? For all the reactants to be over the moles of reactants should be in that ratio. By looking at the data we can say that there's a limiting agent right?
Because here we are given with 3 moles of nitrogen and 5 moles of hydrogen. According to that equation 3 moles should react with 6 moles of hydrogen right?
I want u to do this sum with me ! @Meehan98
Okay, if the ratio is 1:3, shouldn't 3 moles of Nitrogen react with 9 moles of Hydrogen?
Oh yes sorry about that.
So now we know that the limiting agent right?
The limiting reactant would be Nitrogen.
no. See we had 3moles of nitrogen , to react with that we have to have 6 moles of hydrogen. But here we don't have 6 moles. So we have limited amount of Hydrogen. So that will be the limiting reagent. So we will have nitrogen in excess.
Oh okay, I knew that nitrogen was the excess before because I used conversions but just got confused. Now, to figure out how many nitrogen will be left over in the reaction. Do you just subtract the moles of nitrogen from the moles of ammonia?
okay so now we have to find the moles of nitrogen that reacts with 5 moles of hydrogen.
if 3moles of hydrogen will react with 1 mole of nitrogen, how many moles of nitrogen will react with 5 moles of hydrogen.
It would be 5/3 which is 1.67 moles of Nitrogen. Thank you so much!!!
yeah but that's the amount that reacted. TO find the excess amount u have to deduct that from 3moles. :)
Oh, okay. That makes sense. So, it's 1.3 Thank you!
yeah ! anytym :)